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AleksandrR [38]
2 years ago
14

If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.55 x 10-4 T) at a distance of 25

cm, what is the maximum current the wire can carry?
Physics
2 answers:
antiseptic1488 [7]2 years ago
7 0

we are given in the problem the following dimensions or specifications 
B = 0.000055 T r = 0.25 m constant mu0 = 4*pi*10-7 

The formula that is applicable from physics is 
B = mu0*I/(2*pi*r) I = 2*B*pi*r/mu0 I = 68.75 Amperes 
Serga [27]2 years ago
4 0

Answer:

68.75 A

Explanation:

B = 0.55 x 10^-4 T, r = 25 cm = 0.25 m

Let the current be i.

The magnetic field due to a current carrying straight wire at a distance r is given by

B = μ0 / 4π x 2 i / r

0.55 x 10^-4 = 10^-7 x 2 x i / 0.25

i = 68.75 A

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Answer:

formed 4.6 billion years ago

orbit the Sun

range in size from a few feet to more than 500 miles across

most are found in the asteroid belt

Explanation:

Asteroids are rocky bodies orbiting the sun. Asteroids are irregular is shape and size. The size varies from few feet to 500 miles across. Majority of the asteroids lie in asteroid belt which lies between the orbits of Mars and Jupiter. These are though to be remains of unformed planet about 4.6 billion years ago due to high gravitational pull of Jupiter. The largest asteroid is Ceres which is also a dwarf planet. The mass of the entire asteroid belt is just 4% the  mass of the moon.

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2 years ago
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When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room. Which sentence explains t
Vlada [557]

A.

Gases do not have a definite volume.

Explanation:

This observation suggests that the gases do not have a definite volume. Gases moves randomly and will expand to take up the shape of containers they are introduced into.

  • The particles of a gas are very far apart.
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  • Gases are random and they frequently collide with one another and the walls of the containers they are put into.
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3 0
2 years ago
You wad up a piece of paper and throw it into the wastebasket. How far will
vitfil [10]

The range of the piece of paper is C) 1.4 m

Explanation:

The motion of the piece of paper is the motion of a projectile, which consists of two separate motions:

- A uniform motion along the horizontal direction, with constant velocity

- A uniformly accelerated motion along the vertical direction, with constant acceleration (the acceleration of gravity, g=9.8 m/s^2)

From the equation of motion, it is possible to find an expression for the range (the total horizontal distance covered) of a projectile, which is given by:

d=\frac{u^2 sin 2\theta}{g}

where

u is the initial velocity

\theta is the angle of projection

g is the acceleration of gravity

For the piece of paper in this problem,

u = 4.3 m/s

\theta=65^{\circ}

Substituting,

d=\frac{(4.3)^2 sin(2\cdot 65^{\circ})}{9.8}=1.45 m \sim 1.4 m

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brainly.com/question/8751410

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6 0
2 years ago
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A 1000-kg car is slowly picking up speed as it goes around a horizontal curve whose radius is 100 m. The coefficient of static f
Snezhnost [94]

Answer:

18.5 m/s

Explanation:

On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:

\mu mg = m\frac{v^2}{r}

where

\mu is the coefficient of static friction between the tires and the road

m is the mass of the car

g is the gravitational acceleration

v is the speed of the car

r is the radius of the curve

Re-arranging the equation,

v=\sqrt{\mu gr}

And by substituting the data of the problem, we find the speed at which the car begins to skid:

v=\sqrt{(0.350)(9.8 m/s^2)(100 m)}=18.5 m/s

7 0
2 years ago
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A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106
defon

Answer:

4.7\cdot 10^{-14}N

Explanation:

For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:

F=qvB

where

q is the magnitude of the charge

v is the velocity

B is the magnetic field strength

In this problem,

q=1.6\cdot 10^{-19} C

v=6.5\cdot 10^6 m/s

B=4.5\cdot 10^{-2} T

So the force experienced by the electrons is

F=(1.6\cdot 10^{-19}C)(6.5\cdot 10^6 m/s)(4.5\cdot 10^{-2} T)=4.7\cdot 10^{-14}N

3 0
2 years ago
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