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Basile [38]
2 years ago
12

An adult elephant has a mass of about 5.0 tons. An adult elephant shrew has a mass of about 50 grams. How far r from the center

of the Earth should an elephant be placed so that its weight equals that of the elephant shrew on the surface of the Earth
Physics
1 answer:
Diano4ka-milaya [45]2 years ago
4 0

Answer:

2023857702.507m

Explanation:

f=\frac{GMm}{r^{2} }

recall from newton's law of gravitation

G=gravitational constant

mshew=50g

melephant=5*10^3kg

rearth=radius of the earth 6400km or 6400000m

mearth= masss of the earth

Gm(shrew)m(earth)/r(earth)^2 = Gm(elephant)m(earth)/r^2

strike out the left hand side and right hand side variables

m(shrew)/r(earth)^2 = m(elephant)/r^2

r^2 = m(elephant).r(earth)^2 / m(shrew)       .........make r^2 the subject of the equation

r^2=(5*10^{3} *(6400000)^{2} )/.05

r^2=40960000000000

r=2023857702.507m

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3 0
2 years ago
"if a stream flow measures 12 meters in 60 seconds, what is the stream's average rate of flow?"
Vlad [161]
<span>Discharge is the volume of water moving down a stream or river per unit of time, commonly expressed in cubic feet per second or gallons per day. In general, river discharge is computed by multiplying the area of water in a channel cross section by the average velocity of the water in that cross section: discharge = area * velocity. In this case, the answer is 0.2 m/s.</span>
7 0
2 years ago
Two cars start 200 m apart and drive toward each other at a steady 10 m/s. On the front of one of them, an energetic grasshopper
vladimir1956 [14]

Answer:

Total distance does the grasshopper travel before the cars hit is 150 m

Explanation:

Each car moves x=100 m before they collide. Both the cars moving in constant velocity. time taken t by each car is

t=\frac{x}{v}

where x  is the distance traveled with velocity v

t=\frac{100}{10}\\t=10 sec

The insect is moving through this time period with a constant velocity of 15 m/s

The distance traveled by grasshopper  is

distance=V_{gh} \times t\\distance=15 \times 10\\distance=150 m

7 0
1 year ago
If 100 grams of vinegar and 5 grams of baking soda are poured in a container, a small amount of gas will be produced. What will
Anit [1.1K]
It will be a little bit less because of evaporation i learned that in third grade and your in high school that is sad
5 0
2 years ago
If you used 1000 J of energy to throw a ball, would it travel faster if you threw the ball (ignoring air resistance)
wolverine [178]

To solve this problem it is necessary to apply the kinematic equations of Energy for which the rotation of a circular body is described as

KE = \frac{1}{2}mv^2+\frac{1}{2}I\omega^2

Where,

m = Mass of the Vall

v = Velocity

I = Moment of inertia abouts its centre of mass

\omega = Angular speed

Basically the two sums of energies is the consideration of translational and rotational kinetic energy.

a. so that it was also rotating?

The ball is rotating means that it has some angular speed:

KE = \frac{1}{2}mv^2+\frac{1}{2}I\omega^2

1000J = \frac{1}{2}mv^2+\frac{1}{2}I\omega^2

When there is a little angular energy (and not linear energy to travel faster), translational energy will be greater than the 1000J applied.

1000J > \frac{1}{2}mv^2

The ball will not go faster.

c. so that it wasn't rotating?

For the case where the angular velocity does not rotate it is zero therefore

KE = \frac{1}{2}mv^2+\frac{1}{2}I\omega^2

1000J = \frac{1}{2}mv^2+\frac{1}{2}I(0)^2

1000J = \frac{1}{2}mv^2

All energy is transoformed into translational energy so it is possible to go faster. This option is CORRECT.

b. It makes no difference.

Although the order presented is different, I left this last option because as we can see with the previous two parts if there is an affectation regarding angular movement, therefore it is not correct.

6 0
1 year ago
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