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Arte-miy333 [17]
2 years ago
7

To understand the vector nature of momentum in the case in which two objects collide and stick together. In this problem we will

consider a collision of two moving objects such that after the collision, the objects stick together and travel off as a single unit. The collision is therefore completely inelastic. You have probably learned that "momentum is conserved" in an inelastic collision. But how does this fact help you to solve collision problems?
Physics
2 answers:
ludmilkaskok [199]2 years ago
5 0

Answer:

Answer : The momentum is equal to the momentum of object 1 plus the momentum of object 2.

When masses collide with each other and stick together, the collision is said to be inelastic. The kinetic energy before collision and after collision are not equal. For the objects to stick together, they move in the same direction. Therefore the momentum is equal to the momentum of object 1 plus the momentum of object 2.

Explanation:

Plz give me brainliest

vlada-n [284]2 years ago
4 0

Answer:

Applying the law's theory and utilizing the equation of momentum ie. p=mv

Explanation:

The law of conservation of linear momentum states that the momentum in a <em>closed</em> system remains constant. Because a collision is inelastic, this proves that the system is closed. So the equation of momentum is p=mv, p is momentum, m is mass and v is velocity.

Because the momentum is conserved, the momentum (p) before the collision should be equal to the p after the collision, so we can equate them and solve for the unknown:

p=m.v

p(before) = p(after)

m(before) x v(before) = m(after) x v(after)

using this equation, you solve it and this helps you solve collision problems.

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Answer:

Option B, 93 cm

Explanation:

An diagram of the seed's motion is attached to this solution.

This is very close to a projectile motion question. And the quantity to be calculated, how far along the grant a seed released would travel is called the Range.

And this would be obtained from the equations of motion,

First of, the height of the plant is related to some quantities of the motion with this relation.

H = u(y) t + 0.5g(t^2)

U(y) = initial vertical component of velocity = 0 m/s, H = height at which motion began, = 20cm = 0.2 m

That means t = √(2H/g)

The horizontal distance covered, R,

R = u(x) t + 0.5g(t^2) = u(x) t (the second part of the equation goes to zero as the vertical component of the acceleration of this motion is 0)

(substituting the t = √(2H/g) derived from above

R = u(x) √(2H/g)

Where u(x) = the initial horizontal component of the bomb's velocity = maximum initial speed, that is, 4.6 m/s, H = vertical height at which the seed was released = 20 cm = 0.2 m, g = acceleration due to gravity = 9.8 m/s2

R = 4.6 √(2×0.2/9.8) = 0.929 m = 0.93 m = 93 cm. Option B.

QED!

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A Porsche challenges a Honda to a 200-m race.Because the Porsche's acceleration of 3.5 m/s2 is larger than the Honda's 3.0 m/s2,
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Answer:

Honda won by 0.14 s

Explanation:

We are given that

Distance =S=200 m

Initial velocity of Honda=u=0m/s

Initial velocity of Porsche=u'=0m/s

Acceleration of Honda=3.0m/s^2

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Total time taken by Porsche=10.69+1=11.69 s

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Time =11.69-11.55=0.14 s

Honda won by 0.14 s

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