answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dlinn [17]
2 years ago
8

A projectile of mass M, initially at rest, is acted upon by a net force [including gravity] that increases quadratically with ti

me as the projectile accelerates in a vertical gun barrel of length L, Fy = bt2 (1) where b is a constant. After leaving the gun barrel, the time-dependent force vanishes and the projectile rises under gravitational acceleration to a maximum height h above the end of the barrel.
Physics
1 answer:
Elden [556K]2 years ago
7 0

Answer:

maximum height is y = b²/18g √ (12L/b)³

Explanation:

Let's analyze the situation first we have a projectile subjected to an acceleration depends on time, so we must use the definition of acceleration to find the speed when it is at distance L, then we will use the projectile launch equations

Acceleration dependent on t

     a = dv / dt

     dv = adt

     ∫dv =∫ (b t²) dt

     v = b t³ / 3

The initial speed is zero for zero time

 

we use the definition of speed

     v = dy / dt

     dy = v dt

     ∫dy = ∫b t³ / 3 dt

     y = b/3   t⁴ / 4

     y = b/12 t⁴

we evaluate from the initial point where the height is zero for the zero time

Let's calculate the time to travel the length (y = L) of the canyon

     t = (12 y / b) ¼

     t = (12 L / b) ¼

Taking the time, we can calculate the projectile's output speed

     v = b/3  ( (12 L / b)^{3/4}

 

This is the speed of the body, which is the initial speed for the projectile launch movement. Let's calculate the highest point where the zero speed

      Vy² = v₀² - 2 g y

       0 = Vo² - 2 g y

      2 g y = v₀²

      y =  v₀²/ 2g

      y = 1/2g    [b/3 (12L / b^{3/4}) ] 2

      y = 1 / 2g [b²/9  (12L/b)^{3/2}]

      y = b²/18g √ (12L/b)³

You might be interested in
Which three methods are valid for preventing further environmental damage from CO2?
vredina [299]
By afforestation.
by following recycle rule
by not using fossil file in future
3 0
2 years ago
Read 2 more answers
Brian and Jack decided to investigate which water fountain at school has the coldest water. The two boys take measurements using
qaws [65]

Answer:

b

Explanation:

he keep the thermoter in the water longer

3 0
2 years ago
If Emily throws the ball at an angle of 30∘ below the horizontal with a speed of 12m/s, how far from the base of the dorm should
Hitman42 [59]

Answer:

3.6 m

Explanation:

let x = horizontal distance between emily and allison should be for allison to catch the ball

Find horizontal speed of the ball

vx = 12 sin 30 = 12 x 0.5 = 6 m/s

To find time taken, we will use vertical values of the ball motion

Initial velocity in vertical direction

u = 12 cos 30 = 10.392 m/s

let a = g = 9.8m/s2

Use equation of motion

s = ut +1/2at^2

s = vertical distance = 8

8 = (10.392)t + (1/2)(9.8)t^2

8 = (10.392)t + (4.9)t^2

4.9t^2 + 10.392t - 8 = 0

Using formula of quadratic or calculator, we'll find

t = 0.6 and t = -2.72

We pick t=0.6s since it's not logical time in negative

Assuming no air resistance or external forces, the ball will move 6m/s horizontally. Hence using the formula of speed

speed vx = distance x / time

x = (vx)(t)

  = 6 x 0.6

  = 3.6 m

6 0
2 years ago
Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc
xxMikexx [17]

Answer: 14.52*10^6 m/s

Explanation: In order to explain this problem we have to consider the energy conservation for the electron within the coaxial cylidrical wire.

the change in potential energy for the electron; e*ΔV is  equal to energy kinetic gained for the electron so:

e*ΔV=1/2*m*v^2  v^=(2*e*ΔV/m)^1/2= (2*1.6*10^-19*600/9.1*10^-31)^1/2=14.52 *10^6 m/s

3 0
2 years ago
Consider a force of 750 n (roughly the weight of an adult human). over what area (in cm2) would this force need to be applied in
polet [3.4K]
p = \frac{f}{a}
P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
7 0
2 years ago
Other questions:
  • Read the lab procedure for a controlled experiment that looks at the effect of heat on the circumference of bicycle tires.
    7·2 answers
  • A parcel is traveling on a horizontal conveyer belt moving at 1 meter/second. At the end of the conveyor belt, the parcel lands
    9·1 answer
  • Describing the motion of an object can be difficult to do and using graphs help make motion easier to understand. Motion is a ch
    15·2 answers
  • What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?
    9·1 answer
  • A sleepy student drops a calculator out of a window that's 20.7\text{ m}20.7 m20, point, 7, start text, space, m, end text off t
    10·1 answer
  • A woman who weighs 500 N stands on an 8.0-m-long board that weighs 100 N. The board is supported at each end. The support force
    5·1 answer
  • An object moves in a circle of radius R at constant speed with a period T. If you want to change only the period in order to cut
    8·1 answer
  • Determine the values of mm and nn when the following average distance from the Sun to the Earth is written in scientific notatio
    5·1 answer
  • In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law t
    14·1 answer
  • Which phrases describe NASA's goals in the coming years? Check all that apply.
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!