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rewona [7]
1 year ago
5

Two extremely large nonconducting horizontal sheets each carry uniform charge density on the surfaces facing each other. The upp

er sheet carries +5.00 µC/m2. The electric field midway between the sheets is 4.25 × 105 N/C pointing downward. What is the surface charge density on the lower sheet? (ε0 = 8.85 × 10-12 C2/N · m2)
Physics
1 answer:
sashaice [31]1 year ago
8 0

This problem refers to a parallel plate capacitor. There is an electric field between the two plates. The working equation to be used is the Gauss’s Law which is

Electric field = Surface charge density / ε0

The answer is -2.52 μC/m2.

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Julius competes in the hammer throw event. the hammer has a mass of 7.26 kg and is 1.215 m long. what is the centripetal force o
TEA [102]
Centripetal force <span>a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. It is calculated by the expression:

F = mv^2/r

where m is the mass, v is the velocity and r is the radius.

F = 7.26(31.95)^2 / (1.215) = 6100 N</span>
8 0
2 years ago
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Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e
Arlecino [84]

Answer:

The radius is r =  4.434 *10^{-5} \ m

Explanation:

From the question we are told that

    The magnetic field is  B =   90 mT =  90*10^{-3} \ T

     The electron kinetic energy is  KE  =  1.4 eV = 1.4 * (1.60*10^{-19})  =2.24*10^{-19} \ J

Generally for the collision to occur the centripetal force of the electron in it orbit is equal to the magnetic force applied  

   This is mathematically represented as

   \frac{mv^2}{r}  =  qvB

=>    r =  \frac{m* v}{q *  B}

Where  m is the mass of electron with values m  =  9.1 *10^{-31} \ kg  

             v is the escape velocity  which is mathematically represented as

                v  = \sqrt{\frac{2 * KE}{m} }

So  

       r =  \frac{m}{qB}  *  \sqrt{\frac{2 *  KE}{m} }

     apply indices

    r = \frac{\sqrt{2 * KE * m} }{qB}

substituting values

   

        r = \frac{\sqrt{2 * 2.24*10^{-19}* 9.1 *10^{-31}} }{ 1.60 *10^{-19}* 90*10^{-3}}

       r =  4.434 *10^{-5} \ m

     

6 0
1 year ago
A system dissipates 12 J of heat into the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the
timurjin [86]

Answer:

option C

Explanation:

given,

energy dissipated by the system to the surrounding = 12 J

Work done on the system = 28 J

change in internal energy of the system

Δ U = Q - W

system losses energy = - 12 J

work done = -28 J

Δ U = Q - W

Δ U = -12 -(-28)

Δ U = 16 J

hence, the correct answer is option C

6 0
2 years ago
An inventive child named Nick wants to reach an apple in a tree without climbing the tree. Sitting in a chair connected to a rop
Oduvanchick [21]

UHHH WHAT? I DONT GET THAT AT ALLOW

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2 years ago
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harina [27]

Answer:

Too many people are unaware or indifferent to that.” Fines can cost up to $500 per truancy, due within 30 days unless a judge gives an extension. For many students and families, it's another debt they can't pay. And if fines aren't paid, they can convert into an arrest warrant when a student turns 17.

Explanation:

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