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2 years ago

Make a diagram showing the forces acting on a coasting bike rider traveling at 25km/h on a flat roadway.

Physics

2 answers:

Vikentia [17]2 years ago

5 0

Answer: see the figure with the diagram attached.

Explanation:

1) The diagrams showing the forces acting on an object (e.g. a coasting rider) are called free body diagrams.

2) These diagrams consider the object a point, remove all the contacts of the object, and replace all the interactions with force vectors.

3) In the given case, these are the elements that need to be included in the digram:

i) object: the bike rider with the bike. It is represented with a solid dot.

ii) Interaction between the center of the Earth and the object.

A vertical force (vector) pointing downward, whose magnitude equals the weight of the rider and the bike: Weight = mass × g.

It is designated by W.

iii) Interaction betweeen the object and the ground.

A vertical force (vector) pointing upward. It is the reaction force of the ground on the rider/bike. It is responsible for the rider/bike do not fall down toward the Earth.

It is called normal force and designated by N

iv) Force forward.

It is the force that produces the motion forward. It is paralled to the ground (horizontal).

It is directed to the right and desingnated by Ff

v) Resistance and drag force.

Are forces that oppose the motion forward (air resistance and friction with the pavement).

Since, the velocity is told to be constant, the acceleration is zero, so the net force acting is also zero.

That will lead to the fact that the forward motion is equal to the friction and drag forces).

it is horizontal, directed to the left and designated Fr.

Now you can watch and understand the diagram attached.

4) From the diagram and the balance of forces (constant velocity = zero acceleration = zero net force), you can ge the equations of the motion:

Ff = Fr

N = W

valkas [14]2 years ago

3 0

<em>[see the picture attached]

The forces are in red.</em>

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anyanavicka [17]

Answer:

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b) P' = 11062.24 N/m²

Explanation:

Given:

Density of the mercury, ρ = 13.6 × 10³ kg/m³

The blood pressure reading is given as 120 over 83 mm

a) Now,

The pressure (P) due to a fluid is given as:

P = ρgh

where, g is the acceleration due to the gravity

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The systolic pressure head from the blood pressure reading is , h = 120 mm = 0.12 m

substituting the value in the formula for pressure,

we get

P = 13.6 × 10³ × 9.8 × 0.12

P = 15993.6 N/m²

b) The systolic pressure head from the blood pressure reading is , h' = 83 mm = 0.083 m

substituting the value in the formula for pressure,

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P' = 13.6 × 10³ × 9.8 × 0.083

P' = 11062.24 N/m²

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2 years ago

7. Imagine you are pushing a 15 kg cart full of 25 kg of bottled water up a 10o ramp. If the coefficient of friction is 0.02, wh

pentagon [3]

Answer:

The frictional force needed to overcome the cart is 4.83N

Explanation:

The frictional force can be obtained using the following formula:

$F= \mu R$

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R = Normal reaction of the load = $mgcos\theta$ = $25 \times 9.81 \times cos 10$ = $241.52N$

Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.

$F=0.02 \times 241.52N$

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Answer:

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Explanation:

In this case we can see that the first boy Max when he enters the trampoline and jumps creates a harmonic movement, with a given frequency. When the second boy Jimmy enters the trampoline and begins to jump he also creates a harmonic movement. If the frequency of the two movements is the same and they are in phase we have a resonant process, where the amplitude of the movement increases significantly.

Max

x₁ = A cos (wt + Ф)

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x₂ = B cos (wt + Ф)

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Answer:

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