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1 year ago

14

Brass is an alloy made from copper and zinc a 0.59 kg brass sample at 98.0 is dropped into 2.80 kg of water at 5.0 c if the equi

librium temperature is 6.8 what is the specific heat capacity

2 answers:

MariettaO [177]1 year ago

6 0

Answer:

393.399 J/kg.°C

Explanation:

Specific heat capacity: This is the quantity of heat required to raise the temperature of a unit mass of a substance through a degree rise in temperature.

Heat lost by the brass = heat gained by water

CM(t₁-t₃) = cm(t₃-t₂)........................ Equation 1

Where C = specific heat capacity of the brass, M = mass of the brass, t₁ = initial temperature of the brass, t₂ = initial temperature of water, t₃ = temperature of the mixture.

Making C the subject of the equation

C = cm(t₃-t₂)/M(t₁-t₃)............................... Equation 2

Given: M = 0.59 kg, m = 2.8 kg, t₁ = 98 °C, t₂ = 5.0 °C, t₃ = 6.8 °C

Constant: c = 4200 J/kg.°C

Substitute into equation 2,

C = 2.8×4200(6.8-5.0)/0.59(98-6.8)

C = 21168/53.808

C = 393.399 J/kg.°C

Thus the specific heat capacity of the brass = 393.399 J/kg.°C

zhannawk [14.2K]1 year ago

3 0

The specific heat capacity of brass would be ranked between 0 and infinity

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Answer:

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Explanation:

given,

Force exerted by the hydraulic jack piston = F₁ = 250 N

diameter of piston, d₁ = 0.02 m

r₁ = 0.01 m

diameter of second piston, d₂ = 0.15 m

r₂ = 0.075 m

mass of the jack to lift = ?

now,

$\dfrac{F_1}{A_1} =\dfrac{F_2}{A_2}$

$\dfrac{250}{\pi r_1^2} =\dfrac{F_2}{\pi r_2^2}$

$\dfrac{250}{0.01^2} =\dfrac{F_2}{0.075^2}$

$F_2= \dfrac{250}{0.01^2}\times {0.075^2}$

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$m = \dfrac{F}{g}$

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m = 1435 Kg

hence, the correct answer is option B

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2 years ago

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Arte-miy333 [17]

b) Equal to 243 N.

Explanation:

The total force acting on the car in the opposite direction including the road friction and air resistance is equal to 243 N.

This is in conformity with newton's third law of motion.

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The action force is that of the pull by Harry acting on the car.
The reaction force is in the opposite direction.
Both action and reaction force equal and opposite and magnitude and direction

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At one point in the rescue operation, breakdown vehicle A is exerting a force of 4000 N and breakdown vehicle B is exerting a fo

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Answer:

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Let us resolve the two forces into X and Y component

Sum of the forces in the X - component will be 4000 × cos 45 = 2828.43 N

Sum of the forces in the Y - component will be 2000 + ( 4000 × sin 45 )

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= 4828.43 N

The resultant force R will be

R = sqrt ( X^2 + Y^2 )

Substitutes the forces at X component and Y component into the formula

R = sqrt ( 2828.43^2 + 4828.43^2 )

R = sqrt ( 31313752.53 )

R = 5595.87 N

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Substitute Y and X into the formula

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Ø = tan^-1( 1.707106 )

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1 year ago

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It start

FrozenT [24]

Answer:

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after this, the ant travels to

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so, the distance traveled here is

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This is 2 inches to the east.

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2 years ago