Answer:
d = Δv(t2-t1)
Explanation:
Speed is defined as the change of displacement with respect to time. It is expressed as shown;
Speed = change in displacement/change in time
Δv = d/Δt
d = Δv*Δt
d = ΔvΔt
Δt = t2-t1
d = Δv(t2-t1)
Δv is the change in rate of speed
Δt = change in time
The correct expression for the displacement of the car during this motion is d = Δv(t2-t1)
Answer:
Speed, mass and acceleration
Explanation:
A scalar quantity is a quantity that has only magnitude but no direction while a vector quantity has both magnitude and direction.
According to the question, the row that has two scalars and one vector is speed, mass and acceleration.
The two scalars in this row are speed and mass while the vector quantity there is the acceleration.
Acceleration has direction since it possess direction. A body accelerating will do so in a particular direction. Speed and mass doesn't possess any direction. Mass only specify the magnitude of the body but no clue as to which direction is the body moving towards.
Speed also only specify the
total distance covered with respect to time but not the direction of the direction.
F1 = G*m²/D²
<span>F = 2*F1*cos30° = 2*G*50²*cos30°/0.3² = 3.21E-6 </span>
<span>a = F/m = 3.21E-6/50 = 6.42E-8
Hope this helped!
STSN</span>
Answer:
The magnetic force can be found by using the following equation:

Let’s first deal with the magnitude, then we will figure out the direction by using the right hand rule.

The direction of the L is equal to the direction of the current. So, the direction of the L is to the right. The required force is to be pointed upward.
By the right hand rule the magnetic field should be directed towards ‘into the plane’.
Explanation:
In the questions regarding the magnetic field, the cross product and the directions of the vectors are crucial. So, you should use right-hand rule efficiently.
Right-hand rule: 
Point your four fingers (except the thumb) towards the same direction as A.
Point your palm towards the same direction as B.
Your thumb should show the direction of C.
Answer:
The correct relationships are T-fg=ma and L-fg=0.
(A) and (C) is correct option.
Explanation:
Given that,
Weight Fg = mg
Acceleration = a
Tension = T
Drag force = Fa
Vertical force = L
We need to find the correct relationships
Using balance equation
In horizontally,
The acceleration is a
...(I)
In vertically,
No acceleration
Put the value of mg
....(II)
Hence, The correct relationships are T-fg=ma and L-fg=0.
(A) and (C) is correct option.