Answer:

Explanation:
As we know that base of the slab is given as


now we know that rate of heat transfer is given as

here we know that

Also we have



Answer:
7350 J
Explanation:
The gravitational potential energy of the rock sitting on the edge of the cliff is given by:

where
m is the mass of the rock
g is the gravitational acceleration
h is the height of the cliff
In this problem, we have
m = 50 kg
g = 9.8 m/s^2
h = 15 m
Substituting numbers into the formula, we find:

Answer:
Explanation:
Let electric potential at A ,B and C be Va , Vb and Vc respectively.
Work done = charge x potential difference
Wab = q ( Va - Vb )
Wac = q ( Va - Vc )
Given
Wac = - Wab / 3
3Wac = - Wab
Now
Wbc = q ( Vb - Vc )
= q [ ( Va-Vc ) - ( Va - Vb )]
= Wac - Wab
= Wac + 3Wac
= 4Wac
1km=1000m=1000000mm
118km/h=118000000 mm/h
Velocity ... m/s (meters per second) and angle
Acceleration ... m/s^2 and angle
Force ... Newton (kg-m/s^2) and angle
Mass ... kilogram