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erastova [34]
2 years ago
10

Identical cannon balls are fired with the same force, one each from four cannons having respective bore lengths of 1.0 meter, 2.

0 meters, 2.5 meters and 3.0 meters. Which cannon will have the minimum impulse on the ball if the force acting on the ball increases with the length of the bore?
A.) 3.0 meters

B.) 1.0 meters

C.) 2.5 meters

D.) 2.0 meters
Physics
1 answer:
Gala2k [10]2 years ago
4 0

To answer this question, we must bear in mind the following considerations that are mentioned in the statement:

The cannon balls are identical and shoot with the same force

The force acting on the cannonball increases with the length of the hole.

You want to know which cannon will have the least momentum on the ball.

Then, the force on the ball increases as the barrel length increases and the impulse depends on the magnitude of the force, then, the cannon that will have the minimum impulse will be the 1 meter one.

The answer is option B.


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According to Dr. paul Narguizian professor of Biology and Science Education at California State University, ______ are generaliz
Mazyrski [523]

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Explanation:

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1 year ago
If isomerization requires breaking the pi bond, what minimum energy is required for isomerization in j/mol?
aliina [53]
<span>The minimum energy required for isomerization is 267 000 J/mol 
</span>

The isomerization of cis-but-2-ene to trans-but-2-ene requires breaking of the π bond.

The bond energy of a C-C σ bond is 347 kJ/mol.

The bond energy of a C=C double bond (σ + π) is 614 kJ/mol.

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6 0
2 years ago
A firecracker breaks up into several pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.
MakcuM [25]

Answer:

The magnitude of the total momentum is 21.2 kg m/s and its direction is 39.5° from the x-axis.

Explanation:

Hi there!

The total momentum is calculated as the sum of the momenta of the pieces.

The momentum of each piece is calculated as follows:

p = m · v

Where:

p = momentum.

m =  mass.

v = velocity.

The momentum is a vector. The 200 g-piece flies along the x-axis then, its momentum will be:

p = (m · v, 0)

p = (0.200 kg · 82.0 m/s, 0)

p = (16.4 kg m/s, 0)

The 300 g-piece flies along the y-axis. Its momentum vector will be:

p =(0, m · v)

p = (0, 0.300 kg · 45.0 m/s)

p = (0, 13.5 kg m/s)

The total momentum is the sum of each momentum:

Total momentum = (16.4 kg m/s, 0) + (0, 13.5 kg m/s)

Total momentum = (16.4 kg m/s + 0, 0 + 13.5 kg m/s)

Total momentum = (16.4 kg m/s, 13.5 kg m/s)

The magnitude of the total momentum is calculated as follows:

|p| = \sqrt{(16.4 kgm/s)^2+(13.5 kg m/s)^2}= 21.2 kg m/s

The direction of the momentum vector is calculated using trigonometry:

cos θ = px/p

Where px is the horizontal component of the total momentum and p is the magnitude of the total momentum.

cos θ = 16.4 kg m/s / 21.2 kg m/s

θ = 39.3  (39.5° if we do not round the magnitude of the total momentum)

Then, the magnitude of the total momentum is 21.2 kg m/s and its direction is 39.5° from the x-axis.

 

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2 years ago
At the equator, the earth’s field is essentially horizontal; near the north pole, it is nearly vertical. In between, the angle v
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Answer:

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Air has a density of 1.3 kg/m³. Calculate the mass of 36 m³ of air in kilograms. Give your answer to 1 decimal place.
vredina [299]

Answer:

46.8 kg

Explanation:

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= (1.3)(36)

<u>M</u><u>a</u><u>s</u><u>s</u><u> </u><u>=</u><u> </u><u>4</u><u>6</u><u>.</u><u>8</u><u> </u><u>k</u><u>g</u>

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2 years ago
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