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Lapatulllka [165]
2 years ago
15

What is the average acceleration of a car that is initially at rest at a stoplight and then accelerates to 24 m/s in 9.4 s?

Physics
2 answers:
andrezito [222]2 years ago
8 0

brainly.com/question/11542618?answering=true&answeringSource=greatJob%2FquestionPage

topjm [15]2 years ago
5 0

Answer:

B) a= 2.6 m/s²

Explanation:

Conceptual analysis:

Because the car moves with uniformly accelerated movement, we apply the following formula :

vf= v₀+a*t Formula (1)

Where:    

t : time in seconds (s)

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²

Known Data

v₀=0

vf = 24 m/s

t=  9.4

Development problem

We replace the data in the formula (1)

vf= v₀+a*t

24 m/s = 0 + a*9.4s

a =  (24 m/s) / (9.4s)

a= 2.6 m/s²

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A physics student with too much free time drops a watermelon from a roof of a building, hears the sound of the watermelon going
tatiyna

Answer:

28.6260196842 m

Explanation:

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t = Time taken by the watermelon to fall to the ground

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Time taken by the sound to travel the height of the cliff = 2.5-t

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For the watermelon falling

s=ut+\frac{1}{2}at^2\\\Rightarrow h=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow h=\frac{1}{2}\times 9.81\times t^2

For the sound

Distance = Speed × Time

\text{Distance}=340\times (2.5-t)

Here, distance traveled by the stone and sound is equal

\frac{1}{2}\times 9.81\times t^2=340\times (2.5-t)\\\Rightarrow 4.905t^2=340\times (2.5-t)\\\Rightarrow t^2=\frac{340}{4.905}(2.5-t)\\\Rightarrow t^2+69.3170234455t-173.292558614=0

t=\frac{-69.31702\dots +\sqrt{69.31702\dots ^2-4\cdot \:1\cdot \left(-173.29255\dots \right)}}{2\cdot \:1},\:t=\frac{-69.31702\dots -\sqrt{69.31702\dots ^2-4\cdot \:1\cdot \left(-173.29255\dots \right)}}{2\cdot \:1}\\\Rightarrow t=2.4158\ s\ or\ -71\ seconds

The time taken to fall down is 2.4158 seconds

h=\frac{1}{2}\times 9.81\times 2.4158^2=28.6260196842\ m

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