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2 years ago

10. A girl pulls a wagon along a level path for a distance of 44 m. The handle of

Physics

1 answer:

Rina8888 [55]2 years ago

4 0

The work done on the wagon is 3549 J

Explanation:

The work done by a force when moving an object is given by

$W=Fd cos \theta$

where :

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and of the displacement

In this problem we have the following data:

F = 87 N is the magnitude of the force

d = 44 m is the displacement of the wagon

$\theta=22^{\circ}$ is the angle between the direction of the force and the displacement

Substituting, we find the work done

$W=(87)(44)(cos 22^{\circ})=3549 J$

Learn more about work:

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A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction o

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Answer:

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s acceleration has the opposite direction to the car speed.

Explanation:

The initial acceleration of the car can be calculated with

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indicate that the initial velocity is zero (v₀ = 0 m / s)

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the direction of acceleration of the vehicle is the same direction of its acceleration movement.

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2 years ago

Astronauts land on another planet and measure the density of the atmosphere on the planet surface. They measure the mass of a 50

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$1.6 kg/m^3$ is the best estimate of the density of the air on the planet.

Given:

The mass of the conical flask with stopper is 457.23 grams and the volume is $500cm^3$ .

Mass of conical flask and a stopper after removing the air is 456.43 g

To find:

The density of the air on the planet.

Solution;

Mass of the conical flask and stopper with air on the planet= 457.23 g

Mass of conical flask with a stopper and without air on the planet = 456.43 g

Mass of the air in the conical flask on the planet =m

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The volume of the air in the conical flask = $V = 500cm^3$

$1 cm^3=10^{-6} m^3\\\\V= 500cm^3= 500\times 10^{-6}m^3=0.0005 m^3$

The density of the air on the planet = d

$d=\frac{m}{V}\\\\d=\frac{0.0008 kg}{0.0005 m^3}\\\\=1.6 kg/m^3$

$1.6 kg/m^3$ is the best estimate of the density of the air on the planet.

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1 year ago

Two objects exert a gravitational force on 8 N on one another. What would that force be if the mass of BOTH objects were doubled

seropon [69]

<span>Based on Newton's law of universal gravitation, the equation for the gravitational force exerted by an object on another object is given by:
F = Gm1m2/(r^2)
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If the mass of both objects were doubled, then we would have: m1' * m2' = (2m1) * (2m2) = 4m1m2. Assuming r stays constant (G is a constant so that won't change anyway), then this means that the new force will be 4 times greater, ie 8N * 4 = 32N of gravitational force. </span>

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2 years ago

A football player kicks a 0.41-kg football initially at rest; and the ball flies through the air. If the kicker's foot was in co

LUCKY_DIMON [66]

Answer:

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Explanation:

Force = Mass x Acceleration

F = ma

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Initial velocity, u = 0 m/s

Final velocity, v = 21 m/s

Time, t = 0.051 s

Substituting

21 = 0 + a x 0.051

a = 411.76 m/s²

Substituting in force equation,

F = ma = 0.41 x 411.76 = 168.82 N

Average force on the football = 168.82 N

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2 years ago