<span>A = area of styrofoam
M = mass of stryofoam = A*h*rho_s
m = mass of swimmer
Total mass = m + M = m + A*h*rho_s
Downward force = g*(total mass) = g*[m + A*h*rho_s]
The slab is completely submerged.
Buoyant force = g*(mass of water displaced) = g*[A*h*rho_w]
Equate these
g*[m + A*h*rho_s] = g*[A*h*rho_w]
m + A*h*rho_s = A*h*rho_w
A*h*[rho_w - rho_s] = m
A = m/[h*(rho_w - rho_s)]</span>
Answer: The frequency = 1714.3Hz
Explanation: The solution can be achieved by using doppler effect formula.
Since the source is moving toward the observer, the velocity of the observer will be positive.
Please find the attached file for the solution
Answer:
The centripetal force acting on the child is 39400.56 N.
Explanation:
Given:
Mass of the child is, 
Radius of the barrel is, 
Number of revolutions are, 
Time taken for 10 revolutions is, 
Therefore, the time period of the child is given as:
Now, angular velocity is related to time period as:
Now, centripetal force acting on the child is given as:
Therefore, the centripetal force acting on the child is 39400.56 N.
Answer:
Sugar
Explanation:
Nisha's list: Amol's list
Jute Vinegar
Wood Lemon juice
Rubber Cooking soda
Nisha's list is made up of things that can be derived from plants. From the list given, oil, sugar and cotton can also be obtained from plants.
Most plant materials are organic matter.
Amol's list is made up of things that can dissolve in water. Sugar and table salt can also be dissolved in water.
Water is able to dissolve these materials because they are polar compounds. One rule of solubility is that like dissolves like.
New list:
Nisha's list: Amol's list
Jute Vinegar
Wood Lemon juice
Rubber Cooking soda
Sugar Sugar
Only sugar from the list can be added to both lists. It can be obtained from plant and can also dissolve in water.
Let loudness be L, distance be d, and k be the constant of variation such that the equation that would best represent the given above is,
L = k/(d^2)
For Case 1,
L1 = k/(d1^2)
For Case 2,
L2 = k/((d1/4)^2)
For k to be equal, L1 = 16L2.
Therefore, the loudness at your friend's position is 16 times that of yours.
