<span>If two wheels are exactly the same but spin at different speeds, wheel b is twice te speed of wheel a, it is possible to find the ratio of the magnitude of radial acceleration at a singular point of the rim on wheel be to the spot is four.</span>
First, find the needed acceleration needed for the car to stop from its initial velocity given the distance. This is calculated through the equation,
2ad = Vf² - Vi²
where a and d are acceleration and distance, respectively. Vf and Vi are final and initial velocities, respectively. Substituting the known values,
2(a)(35 m) = (0 m/s)² - ((65 km/h) x (1000 m/ 1 km) x (1 hr / 3600 s))²
The value of acceleration is -4.66 m/s².
The force needed to stop the car is the product of the mass and the acceleration. The operations gives us an answer of -4,660 N. We take the positive value, 4,660 N.
Answer: A
Explanation:
Well the high and lows effect the humidity the more humidity the more hot it is so the high brings higher temperatures.
The distance (ft) traveled by the particle at time t (s) is
s(t) = 0.01 t⁴ - 0.02 t³
Part (a)
The velocity at time t is
v(t) = 0.04t³ - 0.06t² ft/s
Part (b)
After 1 s, the velocity is
v(1) = 0.04 - 0.06 = - 0.02 ft/s
Part (c)
When the particle is at rest, the velocity is zero. The time when this happens is given by
0.04t³ - 0.06t² = 0
t²(0.04t - 0.06) = 0
The graph shown below presents a clear picture of the motion.
Answer:
t = 0 (smaller value) or t = 1.5 s (larger value)