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Alexus [3.1K]
1 year ago
5

Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s

ame location as Rock X. Both rocks fall for several seconds before landing on the ground directly below the cliff. Frictional forces are considered to be negligible. After Rock Y is released from rest several seconds after Rock X is released from rest, what happens to the separation distance S between the rocks as they fall but before they reach the ground, and why? Take the positive direction to be downward.
Physics
1 answer:
babunello [35]1 year ago
7 0

Answer:

Separation increases at all times that rock X falls because it falls with a greater speed

Explanation:

For both rocks, let initial velocity ∪=0

To find the displacement at any given time interval of Δt then

S= ∪Δt +0.5gΔt²

Since rock X is first released followed by Y, then X has a greater speed than Y therefore the distance covered by X is longer. This is because despite 0.5gΔt² being same for both rocks at any time Δt but rock X having already attained some velocity, its ∪Δt  is more hence the separation S increases. Conclusively, S increases at all times that rock X falls since rock X falls with a greater velocity than rock Y

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nalin [4]

Answer:

t = 1.02 s

Explanation:

The computation of the time required is shown below:

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And, final velocity = 0

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t = 1.02 s

5 0
1 year ago
A projectile was launched horizontally with a velocity of 468 m/s, 1.86 m above the ground. Calculate how long it would take for
elena-14-01-66 [18.8K]

Answer:

  0.6 seconds

Explanation:

The time to fall from height h is ...

  t = √(2h/g)

  t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.

5 0
2 years ago
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sukhopar [10]

Answer:

1) τ = I α    whereby the torque is provided by the angular acceleration

2)  L = 216 Kg m² / s

Explanation:

1) Let's start with Newton's second law

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multiply by the arm or perpendicular distance

       F r = m a r

if the distance is not perpendicular a way of realizing the relations using the vector product

      τ = F r = F x r

the bold are vectors.  The angular and linear acceleration are related

       a = α r=

         

      τ = m (α r) r

      τ = (m r²) α

the inertia of the rotational motion is

        I = m r²

we substitute

       τ = I α

whereby the torque is provided by the angular acceleration.

As an example we have:

* a spinning disk

* a ball rotating in the air

* a pulley

2) The rotational momentum is

           L = I w

the moment of inertia of a rod that through its center

           I = m L²

we substitute

           L = m L² w

let's calculate

          L = 6 1.5 2 16

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7 0
1 year ago
Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a
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Answer:

Net force acting on them is 16 N and it is acting to the right side.

Explanation:

It is given that,

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Let backward direction is taken to be negative while right side is taken to be positive.

The net force will act in the direction where the magnitude of force is maximum. Net force is given by :

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So, the net force is 16 N and it is acting to the right side.

6 0
2 years ago
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Answer:

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So the average electric field is E=5.7\times 10^{-3}\ V/m.

6 0
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