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2 years ago

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A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b

y the system? (1 l·atm = 101.3 j)

2 answers:

stepan [7]2 years ago

8 0

The work done by a system kept at constant pressure is given by:
$W=p \Delta V = p (V_f - V_i)$
where
p is the pressure
$V_f$ is the final volume
$V_i$ is the initial volume

If we plug the numbers given by the problem into this equation, we find
$W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm$

And since $1 atm \cdot L = 101.3 J$ , we have that the work done is
$W= 1.00 atm \cdot L = 101.3 J$

Airida [17]2 years ago

6 0

The work done by the system is about 101.3 J

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall Work Done by Ideal Gas formula as follows:

$\boxed{ W = \int {P} \, dV }$

<em>where:</em>

<em>P = Gas Pressure ( Pa )</em>

<em>V = Gas Volume ( m³ )</em>

Let us now tackle the problem!

$\texttt{ }$

<u>Given:</u>

initial volume of system = Vo = 1.00 L

final volume of system = V = 2.00 L

constant external pressure = P = 1.00 atm

<u>Asked:</u>

work done by the system = W = ?

<u>Solution:</u>

$W = \int {P} \, dV$

$W = P \Delta V$ ← <em>Constant External Pressure</em>

$W = P ( V - V_o )$

$W = 1.00 ( 2.00 - 1.00 )$

$W = 1.00 ( 1.00 )$

$W = 1.00 \texttt{ L.atm}$

$W = 1.00 \times 101.3 \texttt{ J}$ ← <em>Convert from </em><em>L.atm</em><em> to </em><em>Joule</em>

$\boxed {W = 101.3 \texttt{ J} }$

$\texttt{ }$

<h3>Conclusion:</h3>

The work done by the system is about 101.3 J

$\texttt{ }$

<h3>Learn more</h3>

Buoyant Force : brainly.com/question/13922022

Kinetic Energy : brainly.com/question/692781

Volume of Gas : brainly.com/question/12893622

Impulse : brainly.com/question/12855855
Gravity : brainly.com/question/1724648

$\texttt{ }$

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

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