answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andru [333]
2 years ago
5

Look at these two sentences about Undeposited Funds.1. By posting to Undeposited Funds, you can create a single bank deposit for

multiple payments, making it easy ___________. 2. When receiving a payment, make sure _________________.
Physics
1 answer:
antiseptic1488 [7]2 years ago
4 0

The question with the complete options:

Look at these two sentences about Undeposited Funds. 1. By posting to Undeposited Funds, you can create a single bank deposit for multiple payments, making it easy ___________. 2. When receiving a payment, make sure _________________. Which of the options below correctly fills in the blanks? A.)1. To match your bank register with your bank statement; 2. the Deposit to account is Undeposited Funds

B) 1. To match your bank register with your bank statement; 2. the Deposit to account is Checking

C)1. To match your expenses with your bank statement; 2. the Deposit to account is Uncategorized asset

D)1. To match your bank register with your bank statement; 2. the Deposit to account is Uncategorized funds.

Answer: The correct option is A (1. To match your bank register with your bank statement; 2. the Deposit to account is Undeposited Funds)

Explanation: Undeposited funds is a type of account created to keep funds that are not yet deposited in the individuals account. It's a default account which is used by online marketers to keep funds until they are ready to be paid.

By posting to Undeposited Funds, you can create a single bank deposit for multiple payments, making it easy to match your bank register with your bank statement. When receiving a payment, make sure the Deposit to account is Undeposited Funds.

.

You might be interested in
Which actions most likely cause the domains in a ferromagnetic material to align?
Alexxx [7]

Answer:

A ferromagnetic material is a temporary magnet. The domains in a ferromagnetic material are randomly arranged. Under certain actions, the domains align in a particular direction and the material acts as a magnet. The actions that can cause alignment of domains in a ferromagnetic material are:

  • rubbing the material against a magnet would cause the alignment of domains in the same direction as of the magnet.
  • passing electricity around the material would generate magnetic field which would cause domains to align along the direction of the field.
  • placing the material near a strong magnet would cause the alignment of domains in the direction of the field generated by the strong magnet.

Other actions like heating the material,  placing the material in a magnetic field of opposite polarity and hitting the material would lead to demagnetization of the magnetic material.

8 0
2 years ago
Read 2 more answers
Gold and silicon are mutually insoluble in the solid state and form a eutectic system with a eutectic temperature of 636 k and a
kupik [55]
Yupp its c because my dad farted 
3 0
2 years ago
A 1.5 m cylinder of radius 1.1 cm is made of a complicated mixture materials. Its resistivity depends on the distance x from the
Elis [28]

Answer:

a)R = 171μΩ

b)E = 1.7 *10^{-4} V/m

c)R_{2} = 1.16 *10^{-4}Ω

here * stand for multiplication

Explanation:

length of cylinder = 1.5 m

radius of cylinder  =  1.1 cm

resistivity depends on the distance x from the left

p(x)=a+bx^2 ............(i)

using equation

R = \frac{pl}{a}

let dR is the resistance of thickness dx

dR =\frac{p(x)dx}{a}

where p(x) is resistivity  l is length

a is area

\int\limits^R_0 {dR}  =\frac{1}{\pi r^2} \int\limits^L_0 {(a+bx^2)} \, dx  \\.........................(2)

after integration

R = \frac{[aL+\frac{bL^3}{3}] }{\pi  r^2}  ...............(3)

it is given p(0) = a = 2.25 * 10 ^{-8}Ωm

p(L) = a + b(L)^2  = 8.5 * 10 ^{-8} Ωm

8.5 * 10 ^{-8} = 2.25 * 10^{-8}+b(1.5)^2\\

(here * stand for multiplication )

on solving we get

b = 2.78* 10^{-8} Ωm

put each value of a  and b and r value in equation 3rd we get

R = \frac{[aL+\frac{bL^3}{3}] }{\pi  r^2}

R = 1.71 * 10^{-4}Ω

R = 171μΩ

FOR (b)

for mid point  x = L/2

E = p(x)L

for x = L/2

p(L/2) = a+b(L/2)^2

for given current  I = 1.75 A

so electric field

 

E = \frac{[a+b(L/2)^2]I }{\pi  r^2}

by substitute the values

we get;

E = 1.7 *10^{-4} V/m

(here * stand for multiplication )

c ).

75 cm means length will be half

 that is   x =  L/2

integrate  the second equation with upper limit  L/2  

Let resistance is R_{1}

so after integration we get

R_{1}  =  \frac{[a(L/2) +(b/3)(L^3/8)]}{\pi r^2}

substitute the value of a , b and L we get

R_{1} = 5.47 * 10 ^{-5}Ω

for second half resistance

R_{2} =  R- R_{1}

R_{2}  = 1.7 *10^{-4} -5.47 *10^{-5}

R_{2} = 1.16 *10^{-4}Ω

(here * stand for multiplication )

5 0
2 years ago
¿Alguien me puede ayudar? Problema: Un niño le pide gastada a su papá y éste le contesta que le dará los $120 que tiene en su bo
VLD [36.1K]

Answer: there are 15 coins of $2 and 18 coins of $5

Explanation:

I will answer in English.

X is the number of $5 coins.

Y is the number of $2 coins.

We have the system of equations:

Y + X = 33

Y*2 + X*5 = 120

first, we must isolate one of the variables in one of the equations and then replace it in the other equation, let's isolate Y in the first equation:

Y = 33 - X.

Then we can replace it in the other equation:

(33 - X)*2 + X*5 = 120

66 - X*2 + X*5 = 120

X*3 = 54

X = 54/3 = 18

and using the equation for Y.

Y = 33 - X = 33 - 18 = 15

So there are 15 coins of $2 and 18 coins of $5

3 0
2 years ago
How many slices of bread did each climber have to eat to compensate for the increase of the gravitational potential energy of th
N76 [4]

Answer:

So No of slices to be consumed by each person = n = 65

Explanation:

Energy released by one slice = E1

E1=10^6\ J

h = 8850 m ; m = 79 kg ,η= 10.5%

We know that potential energy given as

u = m g h

u = 79 x 9.81 x 8850

u=6.8\times 10^6\ J

we know from the defination of efficiency that,  η= E(out)/E(in)

Now amount of PE has to be compensated, In our case, E(out) =u

0.105=\dfrac{E(out)}{E(in)}

0.105=\dfrac{6.8\times 10^6}{E(in)}

E(in)=64.76\times 10^6\ J

Let n be the number of bread slices to be consumed.

n = E(in)/E1

n=\dfrac{64.76\times 10^6}{10^6}

n=64.76

So No of slices to be consumed by each person = n = 65

3 0
2 years ago
Other questions:
  • You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s
    14·1 answer
  • A typical male sprinter can maintain his maximum acceleration for 2.0 s, and his maximum speed is 10 m> s. After he reaches t
    10·1 answer
  • A 38 kg crate rests on a floor. A horizontal pulling force of 170 N is needed to start the crate
    15·1 answer
  • You and your friend Peter are putting new shingles on a roof pitched at 20degrees . You're sitting on the very top of the roof w
    5·1 answer
  • The gamma photons created during a PET scan are detected when they encounter a scintillator and produce a burst of light. This l
    11·1 answer
  • The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit t
    9·1 answer
  • For years, space travel was believed to be impossible because there was nothing there Rockets could push off in space in order t
    8·1 answer
  • A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache
    10·1 answer
  • Using your own worlds, write a brief paragraph about: (1) why substitutional vacancies exist in metals and (2) why the equilibri
    8·1 answer
  • As computer structures get smaller and smaller, quantum rules start to create difficulties. Suppose electrons move through a cha
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!