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Luba_88 [7]
2 years ago
6

Describe the distribution of wdiff in terms of its center, shape, and spread, including any plots you use

Physics
1 answer:
melisa1 [442]2 years ago
3 0

Answer:

Figure attached

We can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.

Explanation:

We can use the following R code to obtain the data for wdiff:

source("http://www.openintro.org/stat/data/cdc.R")  #obtain the info

nrow(cdc) # number of elements

names(cdc)  # obtain the name for the variable

[1] "genhlth"  "exerany"  "hlthplan" "smoke100" "height"   "weight"   "wtdesire" "age"      

[9] "gender"  

wdiff represent the difference between desired weight (wtdesire) and current weight (weight) and we can obtain the data with the following code:

wdiff <- (cdc$weight-cdc$wtdesire)

And now we can create the histogram with this code

hist(wdiff,xlim =c(-100,150))

> mean(wdiff)

[1] 14.5891

> median(wdiff)

[1] 10

And the result is on the figure attached.

And we can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.

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A = h / n => h = a*n

a = 0.290 hit / time
n = 300 times

=> h = 0.290 hit / time * 300 time = 87 hits

Answer: 87 hits
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2 years ago
Heat is allowed to flow from the heat source of a heat engine at 425 K to a cold sink at 313 K. What is the efficiency of the he
olga2289 [7]
I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency. 

Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by
\eta = 1- \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the cold temperature
T_{hot} is the hot temperature

For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is
\eta=1- \frac{313 K}{425 K}=0.264 = 26.4 \%
3 0
2 years ago
Read 2 more answers
a fixed mass of a n ideal gas is heated from 50 to 80C at a constant pressure at 1 atm and again at a constant pressure of 3 atm
vitfil [10]

Answer:

The energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.

Explanation:

Given;

initial temperature, t₁ = 50 °C

final temperature, t₂ = 80 °C

Change in temperature, ΔT =80 °C - 50 °C = 30 °C

Pressure for case 1 = 1 atm

Pressure for case 2 = 3 atm

Energy required in both cases is given;

Q = M*C_p*\delta T

where;

Cp is specific heat capacity, which varies only with temperature and not with pressure.

Therefore, the energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.

8 0
2 years ago
A circular loop of wire with radius r=0.0250 m and resistance r=0.390 ohms is in a region of spatially uniform magnetic field. t
slavikrds [6]

Answer:

0.0133 A

Explanation:

The time at which B=1.33 T is given by  

1.33 = 0.38*t^3  

t = (1.33/0.38)^(1/3) = 1.52 s  

Using Faraday's Law, we have  

emf = - dΦ/dt = - A dB/dt = - A d/dt ( 0.380 t^3 )  

Area A = pi * r² = 3.141 *(0.025 *0.025) = 0.00196 m²

emf = - A*(3*0.38)*t^2  

thus, the emf at t=1.52 s is  

emf = - 0.00196*(3*0.38)*(1.52)^2 = -0.0052 V  

if the resistance is 0.390 ohms, then the current is given by  

I = V/R = 0.0052/0.390 = 0.0133 A

3 0
2 years ago
A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st
jeka57 [31]

Answer:

The magnitude of change in momentum is (2mv).

Explanation:

The momentum of an object is given by the product of mass and velocity with which it is moving.

Let the mass of ball is m. A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it struck the wall.

Initial speed of the ball is v and final speed, when it rebounds, is (-v). The change in momentum is given by :

p = final momentum - initial momentum

p=-mv-mv\\\\p=-2mv

So, the magnitude of change in momentum is (2mv).

3 0
2 years ago
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