Describe the distribution of wdiff in terms of its center, shape, and spread, including any plots you use
1 answer:
Answer:
Figure attached
We can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.
Explanation:
We can use the following R code to obtain the data for wdiff:
source("http://www.openintro.org/stat/data/cdc.R") #obtain the info
nrow(cdc) # number of elements
names(cdc) # obtain the name for the variable
[1] "genhlth" "exerany" "hlthplan" "smoke100" "height" "weight" "wtdesire" "age"
[9] "gender"
wdiff represent the difference between desired weight (wtdesire) and current weight (weight) and we can obtain the data with the following code:
wdiff <- (cdc$weight-cdc$wtdesire)
And now we can create the histogram with this code
hist(wdiff,xlim =c(-100,150))
> mean(wdiff)
[1] 14.5891
> median(wdiff)
[1] 10
And the result is on the figure attached.
And we can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.
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Answer:
Explanation:
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Where,
is the enthalpy change
m is the mass
C is the specific heat capacity
is the temperature change
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Mass of water = 2.4 kg
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So,
Heat Supplied
where
Answer:
See explanation below
Explanation:
As I say in the comments, the question is incomplete, however, I will try to answer this by using data that I found on another site.
This is the part of the question that is not here:
If measurements are recorded to the nearest
tenth of a kilogram, find the fraction of these poodles
with weights
(a) over 9.5 kilograms;
(b) of at most 8.6 kilograms;
So, assuming a mean of 8 kg, and 0.9 of standard deviation, let X represents the weight of the poodles
The expression to calculate the fraction of poodle needed is:
Z = X - u / d
u: weight of the large number of poodle
d: standard deviation
Replacing data of a) wer have:
Z = 9.5 - 8 / 0.9
Z = 1.67
With this value, we need to take the value of Z, and see the area under the curve of standard deviation (see table attached)
Therefore:
P (X > 9.5) = P(Z > 1.67) = 0.5 - P (Z < 1.67) = 0.5 - 0.4525 = 0.0475
b) In this part, is the same as part a) so:
Z = 8.6 - 8 / 0.9 = 0.67
The value for area in the curve is 0.2486 so:
P = 0.5 + 0.2486 = 0.7486
Hope this helps
