answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pshichka [43]
2 years ago
13

It takes 87 j of work to stretch an ideal spring, initially 1.4 m from equilibrium, to a position 2.9 m from equilibrium. what i

s the value of the spring constant (force constant) of this spring?
Physics
1 answer:
gayaneshka [121]2 years ago
7 0

Given:

Work done = 87 Joule

x_{1} = 1.4 m

x_{2} = 2.9 m

To find:

Spring constant = ?

Formula used:

W = \frac{1}{2} k \triangle x^{2}

Solution:

Work done required to stretch a spring from 1.4 m to 2.9 m is 87 Joule. Work done is given by following formula.

W = \frac{1}{2} k \triangle x^{2}

where W = work done

k = spring constant or force constant

\triangle x is change in length i. e \triangle x=x_{2} x_{1}

k = \frac{2W}{\triangle x^{2}}

k=\frac{87 \times 2}{[x_{2} - x_{1} ]^{2}}

k = 77.33 N/m

Thus, spring constant of the given spring is 77.33 N/m.

You might be interested in
How, if at all, would the equations written in Parts C and E change if the projectile was thrown from the cliff at an angle abov
sveta [45]

Answer:

x = v₀ cos θ   t ,   y = y₀ + v₀ sin θ t - ½ g t2

Explanation:

This is a projectile launch exercise, in this case we will write the equations for the x and y axes

Let's use trigonometry to find the components of the initial velocity

              sin θ = v_{oy} / v₀

              cos θ = v₀ₓ / v₀

              v_{y} = v_{oy} sin θ

              v₀ₓ = vo cos θ

now let's write the equations of motion

X axis

         x = v₀ₓ t

         x = v₀ cos θ   t

        vₓ = v₀ cos θ

Y axis

        y = y₀ + v_{oy} t - ½ g t2

        y = y₀ + v₀ sin θ t - ½ g t2

        v_{y} = v₀ - g t

       v_{y} = v₀  sin θ - gt

        v_{y}^{2} = v_{oy}^2 sin² θ - 2 g y

As we can see the fundamental change is that between the horizontal launch and the inclined launch, the velocity has components

7 0
2 years ago
Brass is an alloy made from copper and zinc a 0.59 kg brass sample at 98.0 is dropped into 2.80 kg of water at 5.0 c if the equi
zhannawk [14.2K]
The specific heat capacity of brass would be ranked between 0 and infinity
3 0
2 years ago
Read 2 more answers
Human muscles have an efficiency of about __________. A. 9 to 17% B. 18 to 26% C. 27 to 35% D. 36 to 44%
xxTIMURxx [149]

Answer:

The correct answer would be B. 18 to 26%.

The muscle efficiency is calculated by dividing mechanical work output by total metabolic cost.

It is estimated that human muscles have an efficiency of about 18% to 26%.

The efficiency is low because most of the energy is lost when food energy is converted into ATP (adenosine triphophate).

In addition, there is second energy loss when energy in the form of ATP is converted into the mechanical energy such as rowing, cycling et cetera.

3 0
2 years ago
Read 2 more answers
Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be a
marysya [2.9K]

Answer:

The movable piston

Explanation:

Work is said to be done when a distance is been covered by a force . In this case kinetic energy will be change by an equal amount into work done.

Pushing the piston with a known mass of (m) and an accelarating rate from rest of ( a)   to cover a known distance of (d).The idea of work done is been achieved and can be mathematically represented by:

  • Work done = Force x distance (d)
  • Force = mass (m) x acceleration (a)
8 0
2 years ago
A DJ starts up her phonograph player. The turntable accelerates uniformly from rest, and takes t1 = 11.9 seconds to get up to it
Degger [83]

Answer:

a)\omega_1=8.168\,rad.s^{-1}

b)n_1=7.735 \,rev

c)\alpha_1 =0.6864\,rad.s^{-2}

d)\alpha_2=4.1454\,rad.s^{-2}

e)t_2=1.061\,s

Explanation:

Given that:

  • initial speed of turntable, N_0=0\,rpm\Rightarrow \omega_0=0\,rad.s^{-1}
  • full speed of rotation, N_1=78 \,rpm\Rightarrow \omega_1=\frac{78\times 2\pi}{60}=8.168\,rad.s^{-1}
  • time taken to reach full speed from rest, t_1=11.9\,s
  • final speed after the change,  N_2=120\,rpm\Rightarrow \omega_2=\frac{120\times 2\pi}{60}=12.5664\,rad.s^{-1}
  • no. of revolutions made to reach the new final speed,  n_2=11\,rev

(a)

∵ 1 rev = 2π radians

∴ angular speed ω:

\omega=\frac{2\pi.N}{60}\, rad.s^{-1}

where N = angular speed in rpm.

putting the respective values from case 1 we've

\omega_1=\frac{2\pi\times 78}{60}\, rad.s^{-1}

\omega_1=8.168\,rad.s^{-1}

(c)

using the equation of motion:

\omega_1=\omega_0+\alpha . t_1

here α is the angular acceleration

78=0+\alpha_1\times 11.9

\alpha_1 = \frac{8.168 }{11.9}

\alpha_1 =0.6864\,rad.s^{-2}

(b)

using the equation of motion:

\omega_1\,^2=\omega_0\,^2+2.\alpha_1 .n_1

8.168^2=0^2+2\times 0.6864\times n_1

n_1=48.6003\,rad

n_1=\frac{48.6003}{2\pi}

n_1=7.735\, rev

(d)

using equation of motion:

\omega_2\,^2=\omega_1\,^2+2.\alpha_2 .n_2

12.5664^2=8.168^2+2\alpha_2\times 11

\alpha_2=4.1454\,rad.s^{-2}

(e)

using the equation of motion:

\omega_2=\omega_1+\alpha_2 . t_2

12.5664=8.168+4.1454\times t_2

t_2=1.061\,s

4 0
2 years ago
Other questions:
  • A car moving 12 m/s stops in 3 seconds vf=
    15·2 answers
  • A rectangular billboard 5 feet in height stands in a field so that its bottom is 6 feet above the ground. A nearsighted cow with
    5·2 answers
  • 1. Use Coulomb’s Law (equation below) to calculate the approximate force felt by an electron at point A in the schematic below.
    6·1 answer
  • A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c
    6·1 answer
  • A 25-kg iron block initially at 350oC is quenched in an insulated tank that contains 100 kg of water at 18oC. Assuming the water
    13·1 answer
  • Three magnets are placed on a plastic stick as shown in the image. Explain how the magnets need to be rearranged so that they st
    15·2 answers
  • An ice dancer with her arms stretched out starts into a spin with an angular velocity of 1.00 rad/s. Her moment of inertia with
    11·1 answer
  • The surface is tilted to an angle of 37 degrees from the horizontal, as shown above in Figure 3. The blocks are each given a pus
    7·1 answer
  • A 60.0-kg skater begins a spin with an angular speed of 6.0 rad/s. By changing the position of her arms, the skater decreases he
    6·1 answer
  • A skydiver is using wind to land on a target that is 50 m away horizontally. The skydiver starts from a height of 70 m and is fa
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!