It takes 87 j of work to stretch an ideal spring, initially 1.4 m from equilibrium, to a position 2.9 m from equilibrium. what i
1 answer:
Given:
Work done = 87 Joule
= 1.4 m
= 2.9 m
To find:
Spring constant = ?
Formula used:
W =
Solution:
Work done required to stretch a spring from 1.4 m to 2.9 m is 87 Joule. Work done is given by following formula.
W =
where W = work done
k = spring constant or force constant
is change in length i. e
k =
k=
k = 77.33 N/m
Thus, spring constant of the given spring is 77.33 N/m.
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