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2 years ago

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You are flying your Scooty Puff Jr. spaceship at 400 m/s in a direction 40 degrees from the positive y-axis towards the negative

x-axis. You're also accelerating at a rate of 0.5 m/s2 in a direction 30 degrees from the positive x-axis towards the negative y-axis. What is your current velocity?

1 answer:

vazorg [7]2 years ago

7 0

Answer:

Explanation:

Given

velocity of spaceship =400 m/s

at angle of $40^{\circ}$ from Positive Y axis towards negative x axis

acceleration of Spaceship= $0.5 m/s^2$

at an angle of $30^{\circ}$ from positive x axis towards the negative x axis

$\vec{v}=400\left ( -\sin(40)\hat{i}+\cos (40)\hat{j}\right )$

$\vec{v}=-257.11\hat{i}+306.41\hat{j}$

acceleration

$\vec{a}=0.5\left ( \cos (30)\hat{i}-\sin (30)\hat{j}\right )$

$\vec{a}=0.433\hat{i}-0.25\hat{j}$

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Answer:

d) 1.2 mT

Explanation:

Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.

First of all, we observe that:

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I = 15 A

- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).

Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by

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I = 15 A is the current in the conductor

r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field

Substituting, we find:

$B=\frac{(4\pi\cdot 10^{-7})(15)}{2\pi(0.0025)}=1.2\cdot 10^{-3}T = 1.2 mT$

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2 years ago

A TV satellite broadcasts at a frequency of 5000 MHz, (1 MHz = 1 million Hertz). What is the wavelength of this radiation?

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Answer:

$\lambda=0.06\ m$

Explanation:

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A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of

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Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

L= 0.8 m

S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²

ρ = (R*S)/L

ρ= 7.5 * 10⁻⁷ Ω.m

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2 years ago

The atmosphere pressure can support mercury in a tube, which the upper end is closed, up to 0.76 meter. If the mercury is replac

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Answer:

Maximum height the atmosphere pressure can support the

water=10.336 m

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$Density\ of\ mercury =\rho_1\\and\ height\ attained\ for\ mercury\ column = h_1$

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$Density\ of\ water =\rho_2\\and\ height\ attained\ for\ water\ column = h_2$

Since atmospheric pressure is same

. $P=h_1\cdot\rho_1\cdot g = h_2\cdot\rho_2\cdot g$

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2 years ago

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maks197457 [2]

Answer:

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Explanation:

From the question given above, the following data were obtained:

Weight (W) of block = 240 N

Area (A) = 20 cm²

Pressure (P) =?

Next, we shall determine the force exerted by the block. This can be obtained as follow:

Weight (W) of block = 240 N

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Weight and force has the same unit of measurement. Thus, we force applied is equivalent to the weight of the block. Thus,

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