Answer:
None of the option is correct
A=-4µC, B=0 C, C=0 C
C will be +4.0 µC deficient after the contact
Explanation:
A and B are come in contact together, the charge will flow to establish equilibrium, and hence becoming: A=-4µC, B=-4µC, C=+4.0 µC
Similarly when C and B touch, the positive and the negative will exact the same force due to equal charge magnitude and become electrically neutral : A=-4µC, B=0 C, C=0 C.
Answer:
(a) Rm = 268.4 m
(b) f = 6
Explanation:
The horizontal range of a projectile is given by the following formula:
R = V₀² Sin 2θ/g
(a)
For moon:
R = Range on moon = Rm
V₀ = Launch Speed = 28 m/s
θ = Launch Angle = 17°
g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²
Therefore,
Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)
<u>Rm = 268.4 m</u>
(b)
For Earth:
R = Range on Earth = Re
V₀ = Launch Speed = 28 m/s
θ = Launch Angle = 17°
g = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
Re = (28 m/s)²Sin (2*17°)/(9.8 m/s²)
Re = 44.7 m
Therefore.
f = Rm/Re = 268.4 m/44.7 m
<u>f = 6</u>
Answer:
0.56 atm
Explanation:
First of all, we need to find the number of moles of the gas.
We know that
m = 1.00 g is the mass of the gas
is the molar mass of the carbon dioxide
So, the number of moles of the gas is
Now we can find the pressure of the gas by using the ideal gas equation:
where
p is the pressure
is the volume
n = 0.023 mol is the number of moles
is the gas constant
is the temperature of the gas
Solving the equation for p, we find
And since we have
the pressure in atmospheres is
t=5s
it was correct on my do-now
so I hope it was useful for you
Answer:
Mass will be 4.437 kg
Explanation:
We have given force constant k = 7 N/m
Time period of oscillation T = 5 sec
So angular frequency 
We know that angular frequency is given by
Squaring both side
m = 4.437 kg
