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lubasha [3.4K]
1 year ago
11

A force of 50 Newtons causes an object to accelerate at 10 meters per second squared. What is the mass of the object?

Physics
1 answer:
babymother [125]1 year ago
4 0

 Use F = ma, where F is force (in newtons), m is mass (in kg) and a is acceleration (in m/s²).  

In this case F = 50 N and a = 10 m/s², so we have the equation:  

50 = 10m.  

Now divide both sides by 10, getting:  

m = 5 kg.  

So the answer is C. 5.0kg

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Two strings are respectively 1.00 m and 2.00 m long. Which of the following wavelengths, in meters, could represent harmonics pr
MrRissso [65]

Answer:

5) 4.00, 2.00, 1.0

Explanation:

wave equation is given as;

F₀ = V / λ

Where;

F₀ is the fundamental frequency = first harmonic

Length of the string for first harmonic is given as;

L₀ = (¹/₂) λ  

λ  = 2 L₀

when L₀ = 1

λ  = 2 x 1 = 2m

when L₀ = 2m

λ  = 2 x 2 = 4m

For First harmonic, the wavelength is 2m, 4m

For second harmonic;

L₁ = (²/₂)λ  

L₁ = λ

When L₁ = 1

λ  = 1 m

when L₁ = 2

λ  = 2 m

For second harmonic, the wavelength is 1m, 2m

Thus, the wavelength that could represent harmonics present on both strings is 4m, 2m, 1 m

6 0
2 years ago
A parachute works because the canvas of the parachute is acted upon by __________.
Ne4ueva [31]
The question is asking to choose among the following choices that could complete the question about the inertia, base on my research and further investigation, the possible answer would be letter B. Gravity. I hope you are satisfied with my answer and feel free to ask for more 
8 0
2 years ago
Read 2 more answers
Two parallel plates are a distance apart with a potential difference between them. a point charge moves from the negatively char
Ghella [55]

Answer:

We can relate the kinetic energy of the particle to the potential difference between the plates by following equations:

Work energy theorem:

W_{total} = \Delta K = K_2 - K_1 = w - 0

W = Fx\\F = W/d = w/d

F = Eq \\E = F/q = w/(dq)

V = Ed = \frac{w}{dq} d = w/q

So,

w = Vq

If the distance is doubled and the potential difference is halved, then

w = qV/2

Explanation:

As can be seen from the relationship between kinetic energy and the potential difference, the distance between the plates has no effect on the relation between kinetic energy and the potential difference. Since the charge of the second particle is equal to that of the first one, the new kinetic energy would be half of the first kinetic energy.

3 0
2 years ago
A resultant vector is 8.00 units long and makes an angle of 43.0 degrees measured ������� – ��������� with respect to the positi
Komok [63]

Answer:

223 degree

Explanation:

We are given that

Magnitude of resultant vector= 8 units

Resultant vector makes an angle with positive -x in counter clockwise direction

\theta=43^{\circ}

We have to find the magnitude and angle of the equilibrium vector.

We know that equilibrium vector is equal in magnitude  and in opposite direction  to the given vector.

Therefore, magnitude of equilibrium vector=8 units

x-component of a  vector=v_x=vcos\theta

Where v=Magnitude of vector

Using the formula

x-component of resultant  vector=v_x=8cos43=5.85

y-component of resultant vector=v_y=vsin\theta=8sin43=5.46

x-component of equilibrium vector=v_x=-5.85

y-component of equilibrium vector=-v_y=-5.46

Because equilibrium vector lies in III quadrant

\theta=tan^{-1}(\frac{v_x}{v_y})=tan^{-1}(\frac{-5.46}{-5.85})=43^{\circ}

The angle \theta'lies in III quadrant

In III quadrant ,angle =\theta'+180^{\circ}

Angle of equilibrium vector measured from positive x in counter clock wise direction=180+43=223 degree

4 0
1 year ago
A solid steel cylinder is standing (on one of its ends) vertically on the floor. The length of the cylinder is 3.2 m and its rad
maksim [4K]

To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as

\Upsilon = \frac{F/A}{\Delta L/L_0}

Where,

F = Force/Weight

A = Area

\Delta L= Compression

L_0= Original Length

According to the values given we have to

\Upsilon_{steel} = 200*10^9Pa

\Delta L = 5.6*10^{-7}m

L_0 = 3.2m

r= 0.59m \rightarrow A = \pi r^2 = \pi *0.59^2 = 1.0935m^2

Replacing this values at our previous equation we have,

\Upsilon = \frac{F/A}{\Delta L/L_0}

200*10^9 = \frac{F/1.0935}{5.6*10^{-7}/3.2}

F = 38272.5N

Therefore the Weight of the object is 3.82kN

4 0
1 year ago
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