Answer:
The other angle is 30 degrees.
Explanation:
The range of projectile is given by :
Here,
u is the speed of launch of projectile
Here, 
We need to find the other launch angle when the projectile have the same range, such that,
So, the other angle is 30 degrees. Hence, this is the required solution.
The work done is the product between the intensity of the force applied F, the amount of the displacement d of the book and the cosine of the angle
between the direction of the force and the direction of the displacement:
In our problem, the student is lifting the book, so he is applying a force directed upward, and the book is moving upward, so F and d are parallel and therefore the angle is zero, so
Therefore, the work done is
Divide the force given by mass and you will find the acceleration of the object :-
F = m × a
3.63 = 18.15 × a
3.63 = 18.15a
a = 3.63/18.15
a = 0.2 m/s^2
hope it helps!
Answer:
The magnitude of buoyancy force is equal to that of ball's weight.
Explanation:
Ball 1 is floating on water. Weight of ball 1 is Fg=m1g is acting vertically downward
Force of buoyancy FB = ρVdisg is acting vertically upward.
Net force acting on the ball is zero, FB=Fg
Answer
The magnitude of buoyancy force is equal to that of ball's weight.
Answer:
h = 10 m
Explanation:
given,
mass of platform = 50 Kg
Kinetic energy = 5000 J
height from which the diver dove = ?
taking acceleration due to gravity = 10 m/s²
using conservation of energy
Kinetic energy is converted into mechanical energy
K.E = P.E
K.E = m g h
5000 = 50 x 10 x h
500 h = 5000
h = 10 m
The height from which the diver dove is equal to h = 10 m
