Question

A 50-kg platform diver hits the water below with a kinetic energy of 5000 Joules. The height (relative to the water) from which the diver dove was approximately ____ meters.

Answer 1

Answer:

h = 10 m

Explanation:

given,

mass of platform = 50 Kg

Kinetic energy = 5000 J

height from which the diver dove = ?

taking acceleration due to gravity = 10 m/s²

using conservation of energy

Kinetic energy is converted into mechanical energy

K.E = P.E

K.E =  m g h

5000 = 50 x 10 x h

500 h = 5000

 $h = \dfrac{5000}{500}$

    h = 10 m

The height from which the diver dove is equal to h = 10 m