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2 years ago

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A 50-kg platform diver hits the water below with a kinetic energy of 5000 Joules. The height (relative to the water) from which

the diver dove was approximately ____ meters.

1 answer:

artcher [175]2 years ago

6 0

Answer:

h = 10 m

Explanation:

given,

mass of platform = 50 Kg

Kinetic energy = 5000 J

height from which the diver dove = ?

taking acceleration due to gravity = 10 m/s²

using conservation of energy

Kinetic energy is converted into mechanical energy

K.E = P.E

K.E = m g h

5000 = 50 x 10 x h

500 h = 5000

$h = \dfrac{5000}{500}$

h = 10 m

The height from which the diver dove is equal to h = 10 m

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