Answer:
The number of turns is
Explanation:
From the question we are told that
The inner radius is
The outer radius is
The current it carries is
The magnetic field is
The distance from the center is
Generally the number of turns is mathematically represented as
Generally is the permeability of free space with value
So
Answer:
<em>0.45 mm</em>
Explanation:
The complete question is
a certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of 620 A/ cm^2. What is the diameter of the wire in the fuse?
A) 0.45 mm
B) 0.63 mm
C.) 0.68 mm
D) 0.91 mm
Current in the fuse is 1.0 A
Current density of the fuse when it melts is 620 A/cm^2
Area of the wire in the fuse = I/ρ
Where I is the current through the fuse
ρ is the current density of the fuse
Area = 1/620 = 1.613 x 10^-3 cm^2
We know that 10000 cm^2 = 1 m^2, therefore,
1.613 x 10^-3 cm^2 = 1.613 x 10^-7 m^2
Recall that this area of this wire is gotten as
A =
where d is the diameter of the wire
1.613 x 10^-7 =
6.448 x 10^-7 = 3.142 x
=
d = 4.5 x 10^-4 m = <em>0.45 mm</em>
Answer:
Explanation:
<u>Second Newton's Law</u>
It allows to compute the acceleration of an object of mass m subject to a net force Fn. The relation is given by
The net force is the sum of all vector forces applied to the object. The block has two horizontal forces applied (in absence of friction): The 30 N force acting to the right and the 60 N force to the left. The positive horizontal direction is assumed to the right, so the net force is
Thus, the acceleration can be computed by
The negative sign indicates the block is accelerated to the left
Answer:
The final temperature of the object will be 42.785 °C
Explanation:
When the heat added or removed from a substance causes a change in temperature in it, this heat is called sensible heat.
In other words, sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change), so that the temperature varies.
The equation for calculating the heat exchanges in this case is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.
In this case:
Replacing:
450 J= 2.89 *20 g* (Tfinal - 35°C)
Solving for Tfinal:
7.785 °C=Tfinal - 35°C
7.785 °C + 35°C= Tfinal
42.785 °C=Tfinal
<u><em>The final temperature of the object will be 42.785 °C</em></u>