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2 years ago

What is the current through a 25 ohm resistor connected to a 5.0 V power supply? a 0.20 A b 5.0 A c 25 A d 30 A

1 answer:

8 0

~Formula: Voltage= current• resistance
(V= Ir)
~Using this formula, plug in the numbers from the equation into the formula
~5=25i
~Now you have a one-step equation
~Divide by 25 on both sides and you should get your answer:
~I= 0.2 (which means current is 0.2)

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You are riding a rollercoaster going around a vertical loop, on the inside of the loop. If the loop has a radius of 30 meters, h

Debora [2.8K]

Answer:

Speed of the cart at the top of the loop = 34.3 m/s

Explanation:

Gravitational acceleration = g = 9.81 m/s2

Your mass = m

You feel three times as heavy at the top of the loop.

Normal force on you = N = 3mg

Radius of the loop = R

Speed of the cart = V

Centripetal force required for the circular motion = Fc

F = m

The centripetal force is provided by the normal force on you which is directed downwards and your own weight which is directed downwards.

Fc = mg + N

Fc = mg + 3mg

Fc = 4mg

m12 -= 4mg R

V = 4gR

V = 4(9.81)(30)

V = 34.3 m/s

Speed of the cart at the top of the loop = 34.3 m/s

3 0

2 years ago

Read 2 more answers

A professional boxer hits his opponent with a 1025 N horizontal blow that lasts 0.150 s. The opponent's total body mass is 116 k

mylen [45]

Answer:

The impulse is $I = 153.8 \ N \cdot s$

The opponents velocity is $v= 1.33 m/s$

The opponents head recoils velocity $v_r = 30.8 \ m/s$

Explanation:

From the question we are told that

The force of the blow is $F= 1025 \ N$

The duration of the blow is $t = 0.150$

The mass of the opponent is $m_o = 116 \ kg$

The mass of the opponents head is $m_h = 5 \ kg$

The impulse the boxer imparts is mathematically represented as

$I = F * t$

substituting values

$I = 1025 * 0.150$

$I = 153.8 \ N \cdot s$

The impulse can also be mathematically evaluated as

$I = m_o * v$

substituting values

$153.8 = 116 * v$

$v= \frac{153.8}{116}$

$v= 1.33 m/s$

The recoil velocity is mathematically represented as

$v_r = \frac{I}{m_h}$

substituting values

$v_r = \frac{153.8}{5}$

$v_r = 30.8 \ m/s$

5 0

2 years ago

A solid cube of edge length r, a solid sphere of radius r, and a solid hemisphere of radius r, all made of the same material, ar

juin [17]

Answer:

Explanation:

The rate at which heat will be radiated is given by the expression

E = e Aσ ( T⁴ - T₀⁴ )

E is heat radiated , e is emissivity , A is area of surface , σ is stephan's constant T is temperature of the object and T₀ is temperature of the surrounding .

For all the objects given , e , σ T and T₀ are same so E will solely dependent on area of the surface

surface area of cube= 6 r² ,

surface area of sphere = 4 π r²

= 12.56 r²

hemisphere = 2 π r²

= 6.28 r²

12.56 r² >6.28 r² > 6 r²

heat radiated by sphere > heat radiated by hemisphere > heat radiated by cube .

8 0

2 years ago

A projectile follows a straight-line path instead of a parabolic trajectory. Which could be the launch angle? would it be 90 or

Gnesinka [82]

<em>projectile can only follow the straight line path when it is launched upward straightly so the correct option is <u>90 degree with respect to horizontal x -axis ..:)</u></em>

7 0

2 years ago

Read 2 more answers

What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear

faust18 [17]

Answer:

1) The radius of the tire is approximately 0.28966 meters

2) The centripetal force is the force that keeps a body moving on a circular path

Explanation:

1) The linear speed of the automobile tire = 20.0 m/s

The period with which the tire turns = 0.091 s

The period = The time it takes to make a complete turn

Therefore;

The number of turns in 1 second = 1/0.091 ≈ 10.989 turns

The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire

∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire

From the speed of the car, 20.0 m/s, we have;

The distance covered in 1 second = 20.0 meters

Therefore;

10.989 × 2 × π × Radius of the tire = 20.0 meters

Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters

The radius of the tire ≈ 0.28966 meters

2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.

The centripetal force is given by the formula, $F = \dfrac{m \cdot v^2}{r}$

Where;

F = The centripetal force

m = The mass of the object

v = The linear velocity of the object

r = The radius of the rotational motion.

3 0

2 years ago