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SVEN [57.7K]
1 year ago
9

A car is traveling in a race.The car went from initial velocity of 35m/s to the final velocity of 65m/s in 5 seconds what was th

e acceleration
Physics
2 answers:
I am Lyosha [343]1 year ago
8 0
Acceleration is the change in velocity divided by time. The change in velocity is -30m/s and time is 5s. If you divide -30m/s by 5s, you get -6m/s<span>².</span>
OverLord2011 [107]1 year ago
6 0

Answer:

Acceleration, a=6\ m/s^2

Explanation:

Given that,

Initial speed of the car, u = 35 m/s

Final speed of the car, v = 65 m/s

Time taken, t = 5 s

We need to find the acceleration of the car. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{65-35}{5}

a=6\ m/s^2

So, the acceleration of the car is 6\ m/s^2. Hence, this is the required solution.

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Walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity?
storchak [24]
1km per 5 mins
PLEASE VERIFY WITH SOMEONE I MAY BE INCORRECT
7 0
1 year ago
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A housefly walking across a surface may develop a significant electric charge through a process similar to frictional charging.
Umnica [9.8K]

Answer:

Number of electrons, n=3.87\times 10^8\ electrons

Explanation:

Given that,

Charge on the fly, q=62\ pC=62\times 10^{-12}\ C

Let n is the number of electrons lose to the surface it is walking across. It is case of quantization of electric charge. It is given by :

q=ne

n=\dfrac{q}{e}

n=\dfrac{62\times 10^{-12}}{1.6\times 10^{-19}}

n = 387500000 electrons

or

n=3.87\times 10^8\ electrons

So, there are 3.87\times 10^8 electrons. Hence, this is the required solution.

3 0
1 year ago
a ford is traveling with a speed of 15m/s and is 200 meters ahead of a Chevy that is traveling in the same direction but at a sp
Andru [333]
Make an equation for both.
Ford= 15t+200
Chevy=20t
Now you must set them equal and solve for time t. Giving you 40 seconds. Now plug that in to the chevy equation to get 800 meters.
3 0
1 year ago
To determine the y-component of a projectile’s velocity, what operation is performed on the angle of the launch?
koban [17]

<em>To determine the y component of velocity of a projectile </em><u><em>sine </em></u><em>operation is performed on the angle of launch.</em>

<u>Answer:</u> <em>sine</em>

<u>Explanation:</u>

Thus a_x=0,a_y=g

The initial velocity u can be resolved along two directions.

Along the X direction initial velocity = u cos θ

Along y direction initial velocity= u sin θ

From the equation of motion v= u+at

Thus velocity along x direction v_x=u cos θ

Velocity along y direction v_y= u sinθ -gt

Sign of g is negative.

3 0
1 year ago
Read 2 more answers
A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and
snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m

There is a rate of change of the perpendicular component of momentum.

Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

Using formula of momentum

\dfrac{dp}{dt}=F

\dfrac{dP}{dt}=\dfrac{mv^2}{r}

Put the value into the formula

\dfrac{dP}{dt}=\dfrac{27\times10^2}{3.40}

\dfrac{dP}{dt}=794.11\ N

Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.

7 0
2 years ago
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