A bathroom scales works due to gravity. Under normal
conditions, a reading can be obtained when your body is pushing some force on
the scale. However in this case, since you and the scale are both moving
downwards, so your body is no longer pushing on the scale. Therefore the answer
is:
<span>The reading will drop to 0 instantly</span>
The Young modulus is given by:

where
F is the force applied

is the initial length of the wire

is the cross-sectional area of the wire

is the stretch of the wire
The wire in the problem stretches by

of its length, this means

We can also calculate the area of the wire; its radius is in fact half the diameter:

and so the area is

We know the force applied to the wire, F=20 N, so now we have everything to calculate the Young modulus:
<span>Use the kinematic equation vf^2 = vi^2 + 2ad where;
vf = ?
vi = 0 m/s
a = 9.8 m/s^2
d1 = 10 m
d2 = 25 m
final velocity at the ground (d1): vf = sqrt(2)(9.8)(10) = 14 m/s
final velocity to the bottom of the cliff (d2): vf = sqrt(2)(9.8)(25) = 22.14 m/s
</span>
Answer:
d = 0.645 m <em>(assuming a radius of the ball bearing of 3 mm)</em>
Explanation:
<u>The given information is:</u>
- <em>The distance from the center of the sun to the center of the earth is 1.496x10¹¹m =
</em> - <em>The radius of the sun is 6.96x10⁸m =
</em>
<u>We need to assume a radius for the ball bearing, so suppose that the radius is 3 mm =
</u>.
First, we need to find how many times the radius of the sun is bigger respect to the radius of the ball bearing, which is given by the following equation:

Now, we can calculate the distance from the center of the sun to the center of the sphere representing the earth,
:
[tex] d_{s} = \frac{d_{e}}{r_{s}/r_{b}} = \frac{1.496 \cdot 10^{11} m}{2.32\cdot 10^{11}} = 0.645 m
I hope it helps you!
Of course. That's what you have when both objects are at rest. I'm guessing that you left a word out of the question, and it actually says that the net kinetic energy is NOT zero. In that case, the answer is still 'yes', but you have to think about it for a second.