The maximum efficiency of a heat engine operating between 2 degrees c and 200 degrees c will be about:

A 16-Ω loudspeaker, an 8.0-Ω loudspeaker, and a 4.0-Ω loudspeaker are connected in parallel across the terminals of an amplifier

kolbaska11 [484]

Answer:

2.286 ohm

Explanation:

R1 = 16 ohm

R2 = 8 ohm

R3 = 4 ohm

They all are connected in parallel combination

Let the equivalent resistance is R.

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/16 + 1/8 + 1/4

1/R = (1 + 2 + 4) / 16

1/R = 7 / 16

R = 16/7 = 2.286 ohm

6 0

2 years ago

A nervous squirrel gets startled and runs 5.0\,\text m5.0m5, point, 0, space, m leftward to a nearby tree. The squirrel runs for

mel-nik [20]

Answer:

−5.0

Explanation:

6 0

1 year ago

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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00

Aleksandr-060686 [28]

Answer:

Explanation:

We have the following relation between power, P and intensity, I

$I = P/(4*pi*r^2)$

= $10^3/(4*pi*(35000*10^3))$

= $6.5*10^-14 W/M^2$

We also have the following relationship between electric field and electromagnetic radiation thus

$I = (ceE^2)/2$

Hence $E = \sqrt{2I/ce}$

substituting the values of I, c and e, we have

$7*10^-6 V/m$

3 0

1 year ago

A 50 kg rocket generates 990 N of thrust. What will be its acceleration if it is launched straight up?

Ilia_Sergeevich [38]

Answer:

The acceleration of the rocket is 10 m/s².

Explanation:

Let the acceleration of the rocket be $a$ m/s².

Given:

Mass of the rocket is, $m=50\ kg$

Thrust force acting upward is, $F_{th}=990\ N$

Acceleration due to gravity is, $g=9.8\ m/s^2$

Now, force acting in the downward direction is due to the weight of the rocket and is given as:

$W=mg=50\times 9.8=490\ N$

Now, net force acting on the rocket in upward direction is given as:

$F_{net}=F_{th}-W\\F_{net}=990-490=500\ N$

Therefore, from Newton's second law, net force acting on the rocket is equal to the product of mass and acceleration.

$F_{net}=ma\\500=50a\\a=\frac{500}{50}=10\ m/s^2$

Therefore, the acceleration of the rocket is 10 m/s².

4 0

1 year ago

The figure shows two 1.0 kg blocks connected by a rope. a second rope hangs beneath the lower block. both ropes have a mass of 2

lutik1710 [3]

We need first to use the formula F=m(a+g), m iis the total mass, a is the acceleration, g is gravity pulling the blocks. So the procedure will be
m=2kg(both blocks)+500g(both ropes) → m=2.5kg 
a=3.00m/s^2 
g=9.8m/s^2 
F=m(a+g) → F=2.5kg (3.00m/s^2 + 9.8m/s^2) → F=2.5kg (12.8m/s^2) → F=32 N
To calculate the tension at the top of rope 1 you need to use the formula T=m(a+g) so it will be T=m(a+g) → T=1.5kg(12.8m/s^2) → T=19.2N
We can now calculate the tension at the bottom of rope 1 using the formula: T=m(a+g) → T=1.25kg(12.8m/s^2) → T=16N
Now to find the tension at the top of rope 2 we do it like this:
T=m(a+g) → T=.25kg(12.8m/s^2) → T=3.2

7 0

1 year ago

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