Answer:
a. 
b. 
Explanation:
The inertia can be find using
a.





now to find the torsion constant can use knowing the period of the balance
b.
T=0.5 s

Solve to K'


Answer:

Explanation:
Given:
<u>the thermal resistance in the form of </u>


where:
are the thickness of the respective bricks
are the respective coefficient of conductivity
temperature inside the house, 
temperature outside the house, 
area of the wall, 
Since the bricks and insulation are used to construct a wall then they must be used in series for better shielding.
<u>Using Fourier's law:</u>


in series the resistances get add up



Answer:
halved
Explanation:
The velocity of the a wave is obtained by multiplying the frequency and wavelength.

Where
v = Velocity
f = Frequency
= Wavelength
The velocity here is constant. So, if the frequency is doubled the wavelength is halved.
Answer:
a). va=17.23
or 38.54 mph
b). v=38.54 mph and limit is 35 mph
c). Completely inelastic
d). Eka=192.967 kJ
Ekt=76.071 kJ
Explanation:

The motion is an inelastic collision so

The force of the motion is contrarest by the force of friction so

Now with the acceleration can find the time and the velocity final that make the distance 7.25m being united

So the velocity final can be find using this time

a).
Replacing in the first equation the final velocity can find the initial velocity



b).

Velocity limit in m/s is 15.646 m/s and the initial velocity is 17.23 m/s
so is exceeding the speed limit in about 1.58 m/s
or in miles per hour
3.5 mph
c).
The collision is complete inelastic because any mass can be returned to the original mass, so even they are no the same mass however in the moment they move the distance 7.25m as a same mass the motion is considered completely inelastic
d).

Answer:
Δx=(v+v0/2)t
Explanation:
We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.
In this problem, the target unknown is the initial velocity v_0v
0
v, start subscript, 0, end subscript of the roller coaster.