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HACTEHA [7]
2 years ago
5

Consider a person standing in an elevator that is moving at constant speed upward. The person, of mass m, has two forces acting

upon him, the downward force m g due to gravity, and the upward supporting force n exerted by the floor of the elevator. In this case, which of these two forces has the smaller magnitude?

Physics
2 answers:
Leya [2.2K]2 years ago
8 0

Answer:

The force of gravity

Explanation:

Remember that when sometthing is moving there is always several forces acting on the object, in this case, the gravity is pulling the mass of the person standing downward and the floor of the elevator ispulling upward, the direction of the movement will dictate which force is greater than the other, as the person is moving upward that is the greater force, the force of gravity is the smaller magnitude.

larisa [96]2 years ago
4 0

Answer:

The weight of the person has a smaller magnitude.

Explanation:

For an observer in inertial frame of reference for the person in the elevator Newton's Second Law can be written as

Normal reaction acts upwards

Weight acts downwards

\sum F_{v}=ma_{v}\\\\N-mg=m\times a_{v}\\\\m\times a_{v}> 0\\\\\therefore N-mg> 0\\\\\therefore N> mg

Here

N is the normal reaction force

mg is the weight of the person

g is acceleration due to gravity

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T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
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2 years ago
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Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it
lesya692 [45]

Answer:

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

Explanation:

As we know that the mass is revolving with constant angular speed in the circle of radius R

So we will have

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now the position vector at a given time is

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now the linear velocity is given as

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6 0
1 year ago
In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
noname [10]

Answer:

14.7 m/s

Explanation:

a = acceleration experienced by driver's head = 50 g = 50 x 9.8 m/s² = 490 m/s²

v₀ = initial speed of the driver = 0 m/s

v = final speed of the driver after 30 ms

t = time interval for which the acceleration is experienced = 30 ms = 0.030 s

Using the equation

v = v₀ + a t

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v = 0 + (490) (0.030)

v = 14.7 m/s

6 0
2 years ago
A small glider is coasting horizontally when suddenly a very heavy piece of cargo falls out of the bottom of the plane.
myrzilka [38]

Answer:

a. The plane speeds up but the cargo does not change speed.

Explanation:

Just to make it clear, the question is as follows from what I understand.

A small glider is coasting horizontally when suddenly a very heavy piece of cargo falls out of the bottom of the plane.  You can neglect air resistance.

Just after the cargo has fallen out:

a. The plane speeds up but the cargo does not change speed.

b. The cargo slows down but the plane does not change speed.

c. Neither the cargo nor the plane change speed.

d. The plane speeds up and the cargo slows down.

e. Both the cargo and the plane speed up.

And we are requested to choose the right answer under the given conditions. We know the glider has no motor, then it must be in free fall movement, then it is experiencing some force that pulls it to the from due to the gravity effect on it, and a force in general is calculated by

F=m*a, m:= mass of the object, a:= acceleration.

Here we are only considering the horizontal effect of the forces, then since the mass is reduced the acceleration must increase to compensate and maintain  the equilibrium of the forces, then the glider being lighter can travel faster due to the acceleration. On the other hand by the time the cargo left the glider there was no acceleration and the speed it had at the moment he left the plane continues, then the cargo does not change its speed, then horizontally speaking the answer would be a. The plane speeds up but the cargo does not change speed.

5 0
2 years ago
Cylinder A is moving downward with a velocity of 3 m/s when the brake is suddenly applied to the drum. Knowing that the cylinder
Xelga [282]

Answer:

Incomplete question

Check attachment for the given diagram

Explanation:

Given that,

Initial Velocity of drum

u=3m/s

Distance travelled before coming to rest is 6m

Since it comes to rest, then, the final velocity is 0m/s

v=3m/s

Using equation of motion to calculate the linear acceleration or tangential acceleration

v²=u²+2as

0²=3²+2×a×6

0=9+12a

12a=-9

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a=-0.75m/s²

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a=αr

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a is linear acceleration

α is angular acceleration

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α=a/r

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α =3rad/sec²

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b. Time take to come to rest

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v=u+at

0=3-0.75t

0.75t=3

Then, t=3/0.75

t=4 secs

The time take to come to rest is 4s

7 0
2 years ago
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