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VMariaS [17]
2 years ago
6

In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce

leration of 50g that lasts for less than 30 ms, but in a crash with a 50gacceleration lasting longer than 30 ms, a driver is unlikely to survive. Imagine a collision in which a driver's head experienced a 50g accelerationWhat is the highest speed that the car could have had such that the driver survived? Express your answer with the appropriate units.
Physics
1 answer:
noname [10]2 years ago
6 0

Answer:

14.7 m/s

Explanation:

a = acceleration experienced by driver's head = 50 g = 50 x 9.8 m/s² = 490 m/s²

v₀ = initial speed of the driver = 0 m/s

v = final speed of the driver after 30 ms

t = time interval for which the acceleration is experienced = 30 ms = 0.030 s

Using the equation

v = v₀ + a t

Inserting the values

v = 0 + (490) (0.030)

v = 14.7 m/s

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Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t) = 2.6667t2, where t i
Eddi Din [679]

Answer:

averaage speed  is  v = 13 feet / s

Explanation:

 The average speed is the ratio of the distance traveled in a given time interval, let's calculate the distance that the body travels in the two instants of time that give us

   

 t = 1 s

       d (1) = 2.6667 1²

       d (1) = 2.6667 feet

 t = 4 s

       d (4) = 2.6667 4²

       d (4) = 42.6672 feet

Let's calculate the speed

       v = Δx / Δt

       v = (42.6672 -2.6667) / (4-1)

       v = 40/3

        v = 13.33335 feet / s

        v = 13 feet / s

6 0
2 years ago
A person driving a car applies the brakes. This produces friction, which stops the car. Into which type of energy is the mechani
Makovka662 [10]

D) Heat, because friction produces heat, not light, gravitational or chemical. hope this helps! : )

7 0
2 years ago
Read 2 more answers
A brass lid screws tightly onto a glass jar at 20 degrees C. To help open the jar, it can be placed into a bath of hot water. Af
omeli [17]

Answer:

0.0016 cm

Explanation:

\alpha_b = Thermal coefficient of expansion of brass = 19\times 10^{-6}\ /^{\circ}C

\alpha_g = Thermal coefficient of expansion of glass = 9\times 10^{-6}\ /^{\circ}C

\Delta T = Change in temperature = (60-20)^{\circ}C

R_0 = Initial radius = 4 cm

Change in radius of material is given by

R=R_0(1+\alpha\Delta T)

Difference in radii of the lid and jar

\Delta R=R_b-R_g\\\Rightarrow \Delta R=R_0(1+\alpha_b\Delta T)-R_0(1+\alpha_g\Delta T)\\\Rightarrow \Delta R=R_0(\alpha_b-\alpha_g)\Delta T\\\Rightarrow \Delta R=4\times (19\times 10^{-6}-9\times 10^{-6})\times (60-20)\\\Rightarrow \Delta R=0.0016\ cm

The size of the gap is 0.0016 cm or 0.000016 m

8 0
2 years ago
An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc
Afina-wow [57]
The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.

First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity. 

5.5 = (0)(t) + 1/2 (9.81)(t)²
t = 1.06 seconds

Now, we may use this time to determine the horizontal distance covered by the parcel by using:
distance = velocity * time

The horizontal velocity of the parcel will be equal to the horizontal velocity of the cruise liner.

Distance = 10 * 1.06
Distance = 10.6 meters

The boat should be 10.6 meters away horizontally from the point of release.
4 0
2 years ago
A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by
Delicious77 [7]

Answer:

W = -510.98J

Explanation:

Force = 43N, 61° SW

Displacement = 12m, 22° NE

Work done is given as:

W = F*d*cosA

where A = angle between force and displacement.

Angle between force and displacement, A = 61 + 90 + 22 = 172°

W = 43 * 12 * cos172

W = -510.98J

The negative sign shows that the work done is in the opposite direction of the force applied to it.

6 0
2 years ago
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