All categories

2 years ago

A roller of radius 12.5 cm turns at 14 revolutions per second. What is the linear velocity of the roller in meters per second?

Physics

2 answers:

Burka [1]2 years ago

8 0

Answer:

Linear velocity of the roller, v = 11 m/s

Explanation:

It is given that,

Radius of roller, r = 12.5 cm = 0.125 m

Angular velocity of the roller, $\omega=14\ rev/s$

Firstly, we will convert revolution per second to radian per second i.e.

Angular velocity, $\omega=87.96\ rad/s$

We need to find the linear velocity of the roller. It can be calculated by taking the product of angular velocity and the radius of roller.

$v=r\times \omega$

$v=0.125\ m\times 87.96\ rad/s$

v = 10.995 m/s

v = 11 m/s

So, the linear velocity of the roller is 11 m/s. Hence, this is the required solution.

Firdavs [7]2 years ago

7 0

12.5 times 14 and convert to meters its 1.75 meters per second

You might be interested in

If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the

mafiozo [28]

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

Force = 615 N

Time(t) = 1 s

Now, the formula for force is;

Force = mass x acceleration

Thus;

615 = 110 × acceleration

\Acceleration(a) = 615/110 = 5.591 m/s²

Now, using Newton's first law of motion, we can find acceleration (a). Thus;

v = u + at

v = 13.41 + (5.591 × 1)

v ≈ 19 m/s

So,the change in velocity is;

Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s

6 0

2 years ago

According to the author, Picasso’s artistic achievements were in large part the result of his:

Harrizon [31]

Answer:

Picasso’s artistic achievements were in large part the result of his contribution to help bring the Nazi' devastating casual bombing and Spanish civil war in Guernica to the world's attention through his paintings.

4 0

2 years ago

A single slit, which is 0.050 mm wide, is illuminated by light of 550 nm wavelength. What is the angular separation between the

likoan [24]

Answer:

The separation between the first two minima on either side is 0.63 degrees.

Explanation:

A diffraction experiment consists on passing monochromatic light trough a small single slit, at some distance a light diffraction pattern is projected on a screen. The diffraction pattern consists on intercalated dark and bright fringes that are symmetric respect the center of the screen, the angular positions of the dark fringes θn can be find using the equation:

$a\sin \theta_n=n\lambda$

with a the width of the slit, n the number of the minimum and λ the wavelength of the incident light. We should find the position of the n=1 and n=2 minima above the central maximum because symmetry the angular positions of n=-1 and n=-2 that are the angular position of the minima below the central maximum, then:

for the first minimum

$a\sin \theta_1=(1)\lambda$