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MAVERICK [17]
2 years ago
9

A truck covered 2/7 of a journey at an average speed of 40

Physics
2 answers:
slavikrds [6]2 years ago
8 0

Answer:8h

Explanation:

lapo4ka [179]2 years ago
4 0

Answer: 8 km/h

Explanation:

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The small piston of a hydraulic lift has a cross-sectional of 3 00 cm2 and its large piston has a cross-sectional area of 200 cm
Nesterboy [21]

Q: The small piston of a hydraulic lift has a cross-sectional of 3.00 cm2 and its large piston has a cross-sectional area of 200 cm2. What downward force of magnitude must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN?

Answer:

225 N

Explanation:

From Pascal's principle,

F/A = f/a ...................... Equation 1

Where F = Force exerted on the larger piston, f = force applied to the smaller piston, A = cross sectional area of the larger piston, a = cross sectional area of the smaller piston.

Making f the subject of the equation,

f = F(a)/A ..................... Equation 2

Given: F = 15.0 kN = 15000 N, A = 200 cm², a = 3.00 cm².

Substituting into equation 2

f = 15000(3/200)

f = 225 N.

Hence the downward force that must be applied to small piston = 225 N

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Other actions like heating the material,  placing the material in a magnetic field of opposite polarity and hitting the material would lead to demagnetization of the magnetic material.

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