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lesantik [10]
2 years ago
11

1. Which of the following regarding a collision is/are true? a. If you triple your speed your force of impact will be three time

s greater b. Speed has little effect on impact forces c. If you double your speed, the energy dissipated in a crash is four times greater d. If you double your speed, the energy dissipated in a crash is two times greater
Physics
2 answers:
34kurt2 years ago
7 0

Answer:

c

Explanation:

If you double your speed, the energy dissipated in a crash is four times greater

Because impact increases with square of increase in speed.

vlabodo [156]2 years ago
4 0

Answer:

c. If you double your speed, the energy dissipated in a crash is four times greater.

Explanation:

Given:

Impulse, P = force, f × time, t

= mass, m × velocity, v

Energy = kinetic energy, E = 1/2 × m × v^2

At v2 = 2v1

E1 = 1/2 × m × v1^2

= (m × v1^2)/2

E2 = 1/2 × m × (2v1^2)

= 1/2 × m × 4v1^2

= m × 2v1^2

(2 × E1)/v1^2 = E2/2v1^2

E1 = E2/4

E2 = 4 × E1

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The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,900,000 . Determine th
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Here is the complete question

The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,900,000 . Determine the horizontal shear stress at point H, which is located L  = 20 mm below the centriod

The missing image which is the remaining part of this question is attached in the image below.

Answer:

The horizontal shear stress at point H is  \mathbf{\tau_H \approx  42.604 \ N/mm^2}

Explanation:

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\tau_H = \dfrac{80*10^3  * 345625}{64900000*10 }

\tau_H = \dfrac{2.765*10^{10}}{649000000 }

\tau_H = 42.60400616 \ N/mm^2

\mathbf{\tau_H \approx  42.604 \ N/mm^2}

The horizontal shear stress at point H is  \mathbf{\tau_H \approx  42.604 \ N/mm^2}

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