.. A 15.0-kg fish swimming at 1.10 m>s suddenly gobbles up a 4.50-kg fish that is initially stationary. Ignore any drag effec
1 answer:
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Answer:
t = 103.45 n m
Explanation:
given,
refractive index of cornea = 1.38
refractive index of eye drop = 1.45
wavelength of refractive index = 600 nm
refractive index of eye drop is greater than refractive index of cornea and the air.
Formula used in this case
for constructive interference
At m = 0 for the minimum thickness, so
t = 103.45 n m
the minimum thickness of the film of eyedrops t = 103.45 n m
Answer:
Explanation:
Potential due to a charged metallic sphere having charge Q and radius r on its surface will be
v = k Q / r . On the surface and inside the metallic sphere , potential is the same . Outside the sphere , at a distance R from the centre potential is
v = k Q / R
a ) On the surface of the shell , potential due to positive charge is
V₁ =
On the surface of the shell , potential due to negative charge is
V₁ =
Total potential will be zero . they will cancel each other.
b ) On the surface of the sphere potential
=
= 22.5 x 10⁵ V
On the surface of the sphere potential due to outer shell
=
= -9 x 10⁵
Total potential
=( 22.5 - 9 ) x 10⁵
= 13.5 x 10⁵ V
c ) In the space between the two , potential will depend upon the distance of the point from the common centre .
d ) Inside the sphere , potential will be same as that on the surface that is
13.5 x 10⁵ V.
e ) Outside the shell , potential due to both positive and negative charge will cancel each other so it will be zero.
Answer:
0.775
Explanation:
The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:
where
G is the gravitational constant
M is the mass of the planet
m is the mass of the object
R is the radius of the planet
For planet A, the weight of the object is
For planet B,
We also know that the weight of the object on the two planets is the same, so
So we can write
We also know that the mass of planet A is only sixty percent that of planet B, so
Substituting,
Now we can elimanate G, MB and m from the equation, and we get
So the ratio between the radii of the two planets is