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aivan3 [116]
2 years ago
8

If a negative charge is initially at rest in an electric field, will it move toward a region of higher potential or lower potenti

al?What about a positive charge? How does the potential energy of the charge change in each instance? Explain.
Physics
1 answer:
monitta2 years ago
6 0

Answer with explanation :

The negative sign means that the potential energy decreases by the movement of the electron.

negative charge at rest in an electric field moves toward the region of an electric field , so that its potential energy will diminish and change into the kinetic energy of motion. The total energy remains constant.

Positive charges will move downhill because of convention. It is to stay in accordance with other potential theories, particularly gravity, where the "charge" is mass, that moves downwards in the gravitational potential field expressed by ϕ(r)=−GM|r|ϕ(r)=−GM|r|. In an electronic system, howbeit, positive charges are fixed in their position within a component (e.g., a wire), therefore instead of the mobile,the negative charges, electrons, move uphill.

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When a train’s velocity is 12.0 m/s east-ward, raindrops that are falling vertically with respect to the earth make traces that
Elanso [62]

Answer:

a. Horizontal component  v = 12 m/s

b. Magnitude of velocity v = 20.78 m / s  

Explanation:

Vₓ = 12.0 m / s eastward

β = 30.0 °

So

a.

Vt = Vₐ - Vₓ

Vₐ = 0 i

Vt = 0i - 12.0 = - 12 m/s

b.

Vₙ = 12 / sin (30 °)

Vₙ = 24 m / s

Vₙ = 24 * con (30 °)

Vₙ = 20.78 m / s

4 0
2 years ago
An artificial satellite orbits Earth at a speed of 7800 m/s and a height of 200 km above Earth's surface. The satellite experien
MA_775_DIABLO [31]

Answer: less than 9.8 m/s^2 but greater than zero

Explanation:

This answer is correct the other isnt

5 0
1 year ago
A hot air balloon must be designed to support a basket, cords, and one person for a total payload weight of 1300 N plus the addi
RSB [31]

Answer:

r = 4.44 m

Explanation:

 

For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid

         B = ρ g V

Now let's use Newton's equilibrium relationship

         B - W = 0

         B = W

The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)

         σ = W / A

         W = σ A

The area of ​​a sphere is

           A = 4π r²

       W = W₁ + σ 4π r²

The volume of a sphere is

           V = 4/3 π r³

Let's replace

     ρ g 4/3 π r³ = W₁ + σ 4π r²

If we use the ideal gas equation

     P V = n RT

    P = ρ RT

    ρ = P / RT

 

    P / RT g 4/3 π r³ - σ 4 π r² = W₁

    r² 4π (P/3RT  r - σ) = W₁

Let's replace the values

     r² 4π (1.01 10⁵ / (3 8.314 (70 + 273)) r - 0.060) = 13000

     r² (11.81 r -0.060) = 13000 / 4pi

     r² (11.81 r - 0.060) = 1034.51

As the independent term is very small we can despise it, to find the solution

       r = 4.44 m

3 0
2 years ago
A 10-kg dog is running with a speed of 5.0 m/s. what is the minimum work required to stop the dog in 2.40 s?
Tasya [4]
<h3><u>Answer;</u></h3>

<em>Work = 125 joules </em>

<h3><u>Explanation and solution</u>;</h3>
  • Work is the product of force and the distance covered. Therefore, Work = force × distance.
  • Work is measured in joules.
  • Work is also a change in energy, such that work is done when energy changes, so when kinetic energy, or potential energy changes the there is work being done.

Thus; kinetic energy = work done

Kinetic energy = 1/2mv²

                       = 1/2 × 10× 5²

                       = 5 × 25

                       = 125 joules

Hence, work done is 125 joules.

3 0
2 years ago
A cylindrical bar of steel 10.1 mm (0.3976 in.) in diameter is to be deformed elastically by application of a force along the ba
amm1812

Answer:

14778.29 N

Explanation:

Diameter, d=10.1mm= 10.1*10^{-3}m

Since stress, \sigma= \frac {F}{A} where F is force, A is area and since specimen is cylindrical,  

A= \pi *(d/2)^{2}  Therefore, \sigma= \frac {F}{\pi*(0.5d)^{2}}

Also strain \epsilon= \frac { \triangle L}{L} where L is length

Poison’s ratio,v is the ratio of lateral strain to longitudinal strain hence

V= -\frac {\epsilon_{x}}{\epsilon_{z}}= \frac {\triangle dl_{o}}{d \triangle l}

From Hooke’s law, \sigma=E \epsilon_{z}

Conclusively, E* \epsilon_{z}=E* \frac {- \epsilon_{x}}{v}=\frac {F}{\pi*(0.5d)^{2}}

\frac {4F}{ \pi *d^{2}}=- \frac {E \triangle d}{vd}

F=- \frac {\pi *Ed \triangle d}{4v}

F= - \frac {\pi *207*10^{9} *10.1*10^{-3}* (-2.7*10^{-6})}{4*0.3}= 14778.29N

Therefore, required force F is 14778.29 N

3 0
2 years ago
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