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2 years ago

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A11) A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic fiel

d strength is inside the solenoid near its center when a certain current flows through the coils. If the coils of the solenoid are now pulled apart slightly, stretching it to without appreciably changing the size of the coils, what does the magnetic field become near the center of the solenoid when the same current flows through the coils? (μ0 = 4π × 10-7 T • m/A) A) 1.7 mT B) 3.4 mT C) 0.85 mT D) 2.0 mT

1 answer:

vitfil [10]2 years ago

7 0

Answer:

A

Explanation:

From a Solenoid we know that a magnetic fiel is always inversely proportional to lenght L or BL = constant

$B= frac{\mu_0}{2R}$

As I is constant

$\frac{B2}{B1} = \frac{R1}{R2}$

$B2 = 2mT*\frac{18}{21}$

$B2 = 1.714mT$

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