A battleship simultaneously fires two shells toward two identical enemy ships. One shell hits ship A, which is close by, and the
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Answer: East of North
Explanation:
We have the following data:
Speed of the wind from East to West:
Speed of the bee relative to the air:
If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the <u>Speed of the wind from East to West</u> (in the horintal part) and the <u>speed due North relative to the ground</u> (in the vertical part).
Now, we need to find the direction the bee should fly directly to the flower (due North):
Clearing :
If gravitational effects from other objects are negligible, the speed of the rock at a very great distance from the planet will approach a value of
<u>Explanation:</u>
To express velocity which is too far from the planet and escape velocity by using the energy conservation, we get
Rock’s initial velocity
, . Here the radius is R, so find the escape velocity as follows,
Where, M = Planet’s mass and G = constant.
From given conditions,
Surface potential energy can be expressed as,
R tend to infinity when far away from the planet, so
Then, kinetic energy at initial would be,
Similarly, kinetic energy at final would be,
Here,
Now, adding potential and kinetic energies of initial and final and equating as below, find the final velocity as
'm' and as common on both sides, so gets cancelled, we get as
We know, , it can be wriiten as
, we get
Taking squares out, we get,