Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF
To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as
Where,
F = Force/Weight
A = Area
= Compression
= Original Length
According to the values given we have to
Replacing this values at our previous equation we have,
Therefore the Weight of the object is 3.82kN
Answer:
U = 12,205.5 J
Explanation:
In order to calculate the internal energy of an ideal gas, you take into account the following formula:
(1)
U: internal energy
R: ideal gas constant = 8.135 J(mol.K)
n: number of moles = 10 mol
T: temperature of the gas = 100K
You replace the values of the parameters in the equation (1):
The total internal energy of 10 mol of Oxygen at 100K is 12,205.5 J