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Likurg_2 [28]
2 years ago
10

The intensity of sunlight hitting the surface of the earth on a cloudy day is about 0.50 kw/m2 assuming your pupil can close dow

n to a diameter of 2.0 mm and that the average wavelength of visible light is 550 nm, how many photons per second of visible light enter your eye if you look up at the sky on a cloudy day
Physics
1 answer:
GarryVolchara [31]2 years ago
8 0
To determine the number of photons emitted per second, we need data on the total power of the system and the total energy of the photons. We determine the power by multiplying the total area to the intensity of the sunlight given. We do as follows:

Power = 0.50 kW / m^2 ( π (0.001^2)) = 1.57x10^-6 kW = 1.57x10^-3 W

The energy of the visible light can be calculated from the expression:

Energy = hc / wavelength

where h is the planck's constant and c is the speed of light

Energy = (6.63 x 10^-34) (3 x 10^8) / 550 x 10^-9
Energy = 3.62 x 10^-19 J

Number of photons per second =  1.57x10^-3 J/s / 3.62 x 10^-19 J
Number of photons per second = 4.34x10^15 
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A 4.0 Ω resistor, an 8.0 Ω resistor, and a 12.0 Ω resistor are connected in parallel across a 24.0 V battery. What is the equiva
dsp73

PART A)

Equivalent resistance in parallel is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

now we have

\frac{1}{R} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12}

R = 2.18 ohm

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

for 4 ohm resistance we have

24 = 4(i)

i = 6 A

PART C)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

for 8 ohm resistance we have

24 = 8(i)

i = 3 A

3 0
2 years ago
Read 2 more answers
What charge accumulates on the plates of a 2.0-μF air-filled capacitor when it is charged until the potential difference across
enot [183]

Answer:

0.0002 C.

Explanation:

Charge: This can be defined as the ratio of current to time flowing in a circuit. The S.I unit of charge is Coulombs (C)

Mathematically, charge can be expressed as

Q = CV ................................. Equation 1

Where Q = amount of charge, C = capacitance of the capacitor, V = potential difference across the plates.

Given: C = 2.0-μF = 2×10⁻⁶ F, V = 100 V.

Substitute into equation 1

Q = 2×10⁻⁶× 100

Q = 2×10⁻⁴ C

Q = 0.0002 C.

The amount of charge accumulated = 0.0002 C

7 0
1 year ago
Read 2 more answers
A rock is rolling down a hill. At position 1, it’s velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, it’s velo
mr Goodwill [35]

Answer

Hi,

correct answer is {D} 3.5 m/s²

Explanation

Acceleration is the rate of change of velocity with time. Acceleration can occur when a moving body is speeding up, slowing down or changing direction.

Acceleration is calculated by the equation =change in velocity/change in time

a= {velocity final-velocity initial}/(change in time)

a=v-u/Δt

The units for acceleration is meters per second square m/s²

In this example, initial velocity =2.0m/s⇒u

Final velocity=44.0m/s⇒v

Time taken for change in velocity=12 s⇒Δt

a= (44-2)/12  = 42/12

3.5 m/s²

Best Wishes!

5 0
2 years ago
Given a die, would it be more likely to get a single 6 in six rolls, at least two 6s in twelve rolls, or at least one-hundred 6s
vichka [17]

Answer:

Explanation:

In first case we are interested in one time 6 in six rolls

Thus probability = number of chances required/Total chances

= 1/6

Similarly in the second case probability = 2/12 = 1/6

In the same way in last case probability = 100/600 = 1/6

The probability is the same . Thus all the cases has equal chances  

4 0
2 years ago
Which of the following statements is false?
agasfer [191]

A & B

Observe the path of the light ray as it passes through the lenses as shown in the attached images. Concave lenses diverge light rays while the convex lens converges the light rays.

Explanation:

Real images are formed where the rays converge, a property of images by convex lenses. Convex lenses can be used to magnify objects. If the image occurs before the focal point of the lens then the image will be upright but smaller. The images inverts and gets bigger past the focal point.

Virtual images are property of concave lenses. These images appear closer but smaller than the real object.

Learn More:

For more on images formed by lenses check out;

brainly.com/question/6722295

brainly.com/question/12191285

brainly.com/question/12529812

brainly.com/question/11788630

#LearnWithBrainly

6 0
2 years ago
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