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Kazeer [188]
2 years ago
7

Ali hypothesized that increasing fertilizer would increase plant growth. Four groups of thirty similar plants were given 0 to 15

ml of fertilizer, as shown in the graph. The change in plant height for each group over a two-week period was averaged and recorded.
Physics
2 answers:
____ [38]2 years ago
8 0
<span> The hypothesis was not supported; the data indicated that too much fertilizer can inhibit plant growth. hope i helped :D</span>
vagabundo [1.1K]2 years ago
5 0

The hypnotizes was not supported.

It can be noticed that the plants that didn't get any fertilizer tend to grow less than the plants that did get moderate amount of fertilizer, but the plants that were getting much bigger amount of fertilizer didn't performed as expected and they were not growing bigger and better than the other ones. This is because the plants have certain requirements, so if they are surpassed the plants do not get any benefit plus, but instead, it can even cause them damage.

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Which statements describe a situation with a displacement of zero? Check all that apply. traveling south for 30 miles, then turn
velikii [3]
<span>The term "displacement" includes a change of position or change in an innate characteristic. The first option would have someone travel in an L-shape, which definitely is a change in position from the starting point. The second option of Ferris wheel with the same entrance and exit does not involve overall displacement since a person would return to the same place they began. The third option of walking around the block does not involve overall displacement since, again, the person would return to the same place they began. The fourth option of an escalator ride does involve overall displacement because a person would finish their journey in a different vertical location from where they started. The last option does not involve overall displacement because one lap around a track will return you to the same place you began.</span>
5 0
2 years ago
Read 2 more answers
A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m ​ 14, start fraction, start text, m, en
Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

​

 

=

Change in time

Change in velocity

​

=

Δt

v

f

​

−v

i

​

​

​

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

​

v, start subscript, f, end subscript, initial velocity v_iv

i

​

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

​

 

=

Δt

v

f

​

−v

i

​

​

=

3.5s

−21

s

m

​

−(−14

s

m

​

)

​

=−2.0

s

2

m

​

​

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

​

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0
1 year ago
Using a density of air to be 1.21kg/m3, the diameter of the bottom part of the filter as 0.15m (assume circular cross-section),
salantis [7]

Answer:

The  drag coefficient is  D_z  =  1.30512  

Explanation:

From the question we are told that

     The density of air is  \rho_a  = 1.21 \ kg/m^3

     The diameter of bottom part is  d = 0.15 \ m

The  power trend-line  equation is mathematically represented as

      F_{\alpha }  = 0.9226 * v^{0.5737}

let assume that the velocity is  20 m/s

Then

      F_{\alpha }  = 0.9226 * 20^{0.5737}

       F_{\alpha }  = 5.1453 \ N

The drag coefficient is mathematically represented as

      D_z  =  \frac{2 F_{\alpha } }{A \rho v^2 }

Where  

     F_{\alpha } is the drag force

      \rho is the density of the fluid

       v is the flow velocity

       A is the area which mathematically evaluated as

       A = \pi r^2 =  \pi  \frac{d^2}{4}

substituting values

     A =  3.142 *    \frac{(0.15)^2}{4}

     A = 0.0176 \  m^2

Then

   D_z  =  \frac{2 * 5.1453 }{0.0176 * 1.12 *  20^2 }

   D_z  =  1.30512  

3 0
1 year ago
Which of the following situations would violate the second law of<br> thermodynamics?
Musya8 [376]
Heat flows irreversibly from hot to cold
4 0
2 years ago
Read 2 more answers
Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87×106km fr
Andreas93 [3]

Answer:

3494444444.44444 J

-87077491.39453 J

Explanation:

M = Mass of Earth = 6.371\times 10^{6}\ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

R = Radius of Earth = 6.371\times 10^{6}\ m

h = Altitude = 2.87\times 10^9\ m

m = Mass of satellite = 629 kg

v = Velocity of spacecraft = 1.2\times 10^4\ km/h

The kinetic energy is given by

K=\frac{1}{2}629\times \left(1.2\times 10^4\times \dfrac{1000}{3600}\right)^2\\\Rightarrow K=3494444444.44444\ J

The spacecraft's kinetic energy relative to the earth is 3494444444.44444 J

Potential energy is given by

U=-\dfrac{GMm}{R_e+h}\\\Rightarrow U=-\dfrac{6.67\times 10^{-11}\times 5.97\times 10^{24}\times 629}{2.87\times 10^9+6.371\times 10^{6}}\\\Rightarrow U=-87077491.39453\ J

The potential energy of the earth-spacecraft system is -87077491.39453 J

4 0
1 year ago
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