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Kazeer [188]
2 years ago
7

Ali hypothesized that increasing fertilizer would increase plant growth. Four groups of thirty similar plants were given 0 to 15

ml of fertilizer, as shown in the graph. The change in plant height for each group over a two-week period was averaged and recorded.
Physics
2 answers:
____ [38]2 years ago
8 0
<span> The hypothesis was not supported; the data indicated that too much fertilizer can inhibit plant growth. hope i helped :D</span>
vagabundo [1.1K]2 years ago
5 0

The hypnotizes was not supported.

It can be noticed that the plants that didn't get any fertilizer tend to grow less than the plants that did get moderate amount of fertilizer, but the plants that were getting much bigger amount of fertilizer didn't performed as expected and they were not growing bigger and better than the other ones. This is because the plants have certain requirements, so if they are surpassed the plants do not get any benefit plus, but instead, it can even cause them damage.

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A densly wound cylindrical coil has 210 turns per meter, a 5 cm radius, and carries 38 mA. What is the magnitude of the uniform
kaheart [24]

Answer:

(a). The magnitude of the uniform magnetic field is 10.02 μT

(b). The the magnitude of the total magnetic field is 10.78 μT.

Explanation:

Given that,

Number of turns = 210

Radius = 5 cm

Current = 38 mA

Current in the wire = 500 mA

We need to calculate the magnetic field inside a coil

Using formula of magnetic field

B=\mu_{0} ni

Put the value into the formula

B_{c}=4\pi\times10^{-7}\times210\times38\times10^{-3}

B_{c}=0.0000100\ T

B_{c}=10.02\times10^{-6}\ T

Now a straight wire is inserted into the coil that carries 500 mA. It travels down the central axis of the coil

Distance d=\dfrac{5}{2}

d=2.5\ cm

We need to calculate the magnetic field from the straight wire

Using formula of magnetic field

B_{w}=\dfrac{\mu_{0}I}{2\pi d}

Put the value into the formula

B_{w}=\dfrac{4\pi\times10^{-7}\times500\times10^{-3}}{2\times\pi\times2.5\times10^{-2}}

B_{w}=4.0\times10^{-6}\ T

This field is perpendicular to the wire.

The magnitude of magnetic field is

B=\sqrt{B_{c}^2+B_{w}^2}

B=\sqrt{(10.02\times10^{-6})^2+(4.0\times10^{-6})^2}

B=0.00001078\ T

B=10.78\times10^{-6}\ T

B=10.78\ \mu\ T

Hence, (a). The magnitude of the uniform magnetic field is 10.02 μT

(b). The the magnitude of the total magnetic field is 10.78 μT.

6 0
1 year ago
A quarterback throws a football with an initial velocity v at an angle θ above horizontal. Assume the ball leaves the quarterbac
Maru [420]
(a) The y-component or vertical velocity is calculated using:
Vy = Vsin(∅)

(b) The x-component or horizontal velocity is calculated using:
Vx = Vcos(∅)
6 0
2 years ago
If this energy were used to vaporize water at 100.0 ∘C, how much water (in liters) could be vaporized? The enthalpy of vaporizat
Zanzabum

Answer:

0.429 L of water

Explanation:

First to all, you are not putting the value of the energy given to vaporize water, so, to explain better this problem, I will assume a value of energy that I took in a similar exercise before, which is 970 kJ.

Now, assuming that the water density is 1 g/mL, this is the same as saying that 1 g of water = 1 mL of water

If this is true, then, we can assume that 1 kg of water = 1 L of water.

Knowing this, we have to use the expression to get energy which is:

Q = m * ΔH

Solving for m:

m = Q / ΔH

Now "m" is the mass, but in this case, the mass of water is the same as the volume, so it's not neccesary to do a unit conversion.

Before we begin with the calculation, we need to put the enthalpy of vaporization in the correct units, which would be in grams. To do that, we need the molar mass of water:

MM = 18 g/mol

The enthalpy in mass:

ΔH = 40.7 kJ/mol / 18 g/mol = 2.261 kJ/g

Finally, solving for m:

m = 970 / 2.261 = 429 g

Converting this into volume:

429 g = 429 mL

429 / 1000 = 0.429 L of water

3 0
2 years ago
This is a physical property of all visible light determined by the light's frequency and visible to the human eye.
motikmotik
Color <span>is a physical property of all visible light determined by the light's frequency and visible to the human eye.</span>
6 0
1 year ago
8) A flat circular loop having one turn and radius 5.0 cm is positioned with its plane perpendicular to a uniform 0.60-T magneti
Marrrta [24]

Answer:

EMF induced in the loop is 9.4 V

Explanation:

As we know that initial magnetic flux of the loop is given as

\phi_1 = B.A

\phi_1 = (0.60)(\pi (0.05)^2)

\phi_1 = 4.7 \times 10^{-3} Wb

As soon as the area of the loop becomes zero the final magnetic flux of the loop is ZERO

Now as per faraday's law of electromagnetic induction the EMF is induced due to rate of change in magnetic flux

so we will have

EMF = \frac{\Delta \phi}{\Delta t}

so we will have

EMF = \frac{4.7 \times 10^{-3} - 0}{0.50 \times 10^{-3}}

EMF = 9.4 V

7 0
2 years ago
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