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Ksivusya [100]
2 years ago
9

To move a suitcase up to the check-in stand at the airport a student pushes with a horizontal force through a distance of 0.95 m

. If the work done by the student is 32 J, what is the magnitude of the force he exerts?
Physics
1 answer:
hoa [83]2 years ago
3 0

Answer:

33.68 N

Explanation:

Data

W= 32J

d- 0.95m

F= ?

W=Fd

They are asking for the magnitude which is the force, so you need to solve for force.

F=W/d

= 32J/ 0.95m

= 33.68 N

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Levi observed properties of four different waves and recorded observations about each one in his chart. A 2-column table with 4
makvit [3.9K]

Answer:

Wave W is a sound wave, Waves X and Y are light waves, and it is impossible to tell what kind of wave Wave Z is.

Explanation:

W      travels fastest through metal

X       travels fastest through air,

Y       travels more slowly through water than air    

Z       travels more slowly at cool temperatures

W appears to be sound wave  as sound travels fastest through metal .

X appears to be light wave as light travels fastest in air .

Y also appears to be light wave as  speed of light is reduced when it passes from air to water .

Z  It is impossible to tell anything about the nature of Z wave .

5 0
2 years ago
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A diver explores a shallow reef off the coast of Belize. She initially swims d1 = 74.8 m north, makes a turn to the east and con
Nataly [62]

Answer:R=1607556m

θ=180degrees

Explanation:

d1=74.8m

d2=160.7km=160.7km*1000

d2=160700m

d3=80m

d4=198.1m

Using analytical method :

Rx=-(160700+75*cos(41.8))= -160755.9m

Ry= -(74.8+75sin(41.8))-198.1=73m

Magnitude, R:

R=√Rx+Ry

R=√160755.9^2+20^2=160755.916

R=160756m

Direction,θ:

θ=arctan(Rx/Ry)

θ=arctan(-73/160755.9)

θ=-7.9256*10^-6

Note that θ is in the second quadrant, so add 180

θ=180-7.9256*10^6=180degrees

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2 years ago
In the system shown above, the pulley is a uniform disk with a mass of .75 kg and a radius of 6.5 cm. The coefficient of frictio
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Answer:

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5 0
2 years ago
Convert the volume 8.06 in.3 to m3, recalling that1in. =2.54cmand100cm=1m. Answer in units of m3.
galina1969 [7]
1 in=2.54 cm=(2.54 cm)(1 m/100 cm)=0.0254 m
Therefore:
1 in=0.0254 m
1 in³=(0.0254 m)³=1.6387064 x 10⁻⁵ m³

Therefore:

8.06 in³=(8.06 in³)(1.6387064 x 10⁻⁵ m³ / 1 in³)≈1.321 x 10⁻⁴ m³.

Answer: 8.06 in³=1.321 x 10⁻⁴ m³
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2 years ago
a projectile is launched straight up at 141 m/s . How fast is it moving at the top of its trajectory? suppose it is launched upw
BARSIC [14]

The velocity of projectile has 2 components, horizontal component vcosθ and vertical component vsinθ, where v is the velocity of projection and θ is the angle between +ve X-axis and projectile motion.

In case 1, θ = 90⁰

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In case 2, θ = 45⁰

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         Vertical component at maximum height = 0

So velocity at maximum height = 100 m/s


7 0
2 years ago
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