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slavikrds [6]
2 years ago
14

Particle q1 has a positive 6 µC charge. Particle q2 has a positive 2 µC charge. They are located 0.1 meters apart.

Physics
2 answers:
m_a_m_a [10]2 years ago
3 0

Answer:

F = 10.788 N

Explanation:

Given that,

Charge 1, q_1=6\ \mu C=6\times 10^{-6}\ C

Charge 2, q_2=2\ \mu C=2\times 10^{-6}\ C

Distance between charges, d = 0.1 m

We know that there is a force between charges. It is called electrostatic force. It is given by :

F=\dfrac{kq_1q_2}{d^2 }\\\\F=\dfrac{8.99\times 10^9\times 6\times 10^{-6}\times 2\times 10^{-6}}{(0.1)^2 }\\\\F=10.788\ N

So, the force applied between charges is 10.788 N.

Margaret [11]2 years ago
3 0

Answer:

10.8 N

Explanation:

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While practicing S-turns, a consistently smaller half-circle is made on one side of the road than on the other, and this turn is
erica [24]

Answer:

The answer is "4-5-6 because the bank is growing too quickly in the beginning of its turn".

Explanation:

The S-turns is also known as the reference technique, in which the ground track of the aircraft on both sides of a defined ground-based straight-line distance represents 2 different but equivalent circles.  

Throughout the S-turns, on either side of the road, a progressively smaller half-circle is formed, and this turn does not stop until the road or reference line is crossed during the early part of the turn, the twists increase too quickly.

5 0
1 year ago
The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
Troyanec [42]

Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

L = Length of the human ear canal = 2.5 cm = 0.025 m

V = Speed of sound = 340 ms⁻¹

f = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

f = \frac{(2n - 1)V}{4L}

for first resonant frequency, we have n = 1

Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

4 0
2 years ago
A small ball of mass 2.00 kilograms is moving at a velocity 1.50 meters/second. It hits a larger, stationary ball of mass 5.00 k
rewona [7]

The kinetic energy of the small ball before the collision is

                             KE  =  (1/2) (mass) (speed)²

                                     = (1/2) (2 kg) (1.5 m/s)

                                     =    (1 kg)  (2.25 m²/s²)

                                     =        2.25 joules.

Now is a good time to review the Law of Conservation of Energy:

                     Energy is never created or destroyed. 
                     If it seems that some energy disappeared,
                     it actually had to go somewhere.
                     And if it seems like some energy magically appeared,
                     it actually had to come from somewhere.

The small ball has 2.25 joules of kinetic energy before the collision.
If the small ball doesn't have a jet engine on it or a hamster inside,
and does not stop briefly to eat spinach, then there won't be any
more kinetic energy than that after the collision.  The large ball
and the small ball will just have to share the same 2.25 joules.

3 0
2 years ago
13. A hiker walks 200 m west and then walks 100 m north. In what direction is her resulting displacement?
prohojiy [21]
100m north west   is the answer                                      
4 0
2 years ago
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In which situation is the object experiencing unbalanced forces? A) A box resting on a horizontal floor. B) A car slowing as it
evablogger [386]

"Unbalanced forces" show themselves as a change in the speed
or direction of an object's motion.

The only choice where the speed or direction of motion is changing
is the car that's slowing down for the light.

3 0
2 years ago
Read 2 more answers
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