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STALIN [3.7K]
2 years ago
10

The standard acceleration (at sea level and 45◦ latitude) due to gravity is 9.806 65 m/s2. What is the force needed to hold a ma

ss of 2 kg at rest in this gravitational field? How much mass can a force of 1 N support?
Physics
1 answer:
erma4kov [3.2K]2 years ago
5 0

a) Remember Newton's second Law:

F = m*a

This means that the forces that is being exerted over an object is equal to the mass of the object times the acceleration that it has.

In this case, in order to hold the mass you need a force with the same magnitude but opposite direction to the gravitational force. The magnitude of this force would be the mass of the object times the gravitactional  acceleration:

F = 2kg*9.80665m/s² = 19.6133 N

b) Using again Newton's second Law, we can issolate mass from that equation:

m = F/a

Then, the mass that a force of 1N can support is equal to:

m = 1N/9.80665m/s² = 0.102 kg

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Given that,

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2 years ago
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550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c
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Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

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7 0
2 years ago
How many significant figures do each of the following numbers have: (a) 214, (b) 81.60, (c) 7.03, (d) 0.03, (e) 0.0086, (f) 3236
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<span>Second: Any zeros located between  non zeroes are always significant.</span>

Third: A zero located after a non zero in a decimal is always significant whether it is before or after the decimal

 

Therefore using this rule, the number of significant digits in the given numbers are:

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(b) 81.60 = 4

(c) 7.03 = 3

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(f) 3236 = 4

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