An electron is projected with an initial speed of 3.9 × 105 m/s directly toward a proton that is fixed in place. If the electron
is initially a great distance from the proton, at what distance from the proton is the speed of the electron instantaneously equal to 8 times the initial value?
1 answer:
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Answer:
Change in kinetic energy is ( 26CL³)/3
Explanation:
Given :
Net force applied, F(x) = Cx² ....(1)
Displacement of the particle from xi = L to xf = 3L.
The work-energy theorem states that change in kinetic energy of the particle is equal to the net amount of work is done to displace the particle.
That is,
ΔK = W = ∫F·dx
Substitute equation (1) in the above equation.
ΔK = ∫Cx²dx
The limit of integration from xi = L to xf = 3L, so
Substitute the values of xi and xf in the above equation.