An electron is projected with an initial speed of 3.9 × 105 m/s directly toward a proton that is fixed in place. If the electron
is initially a great distance from the proton, at what distance from the proton is the speed of the electron instantaneously equal to 8 times the initial value?
1 answer:
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Answer:
5.843 m
Explanation:
suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.
lets consider that horizontal motion
distance = speed * time
time = 40/ 37 = 1.081 s
arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.
applying motion equation
(assume g = 10 m/s²)
Arrow misses the target by 5.843m ig the arrow us split horizontally
