An electron is projected with an initial speed of 3.9 × 105 m/s directly toward a proton that is fixed in place. If the electron
is initially a great distance from the proton, at what distance from the proton is the speed of the electron instantaneously equal to 8 times the initial value?
1 answer:
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The average velocity of Sandy is given by the total distance covered S divided by the total time taken t:
The total distance covered is
while the total time taken is 2 hours + half an hour (for the rest) + 1 hour and half, so
Therefore, the average velocity is
The total distance covered is
while the total time taken is 2 hours + half an hour (for the rest) + 1 hour and half, so
Therefore, the average velocity is
Explanation:
It is given that,
The horizontal speed of a cliff diver,
It reaches the water below 2.00 s later, t = 2 s
Let is the distance where the diver hit the water. It can be calculated as follows :
Let is the height of the cliff. It can be calculated using second equation of motion as follows :
So, the cliff is 19.6 m high and it will hit the water at a distance of 19.6 m.