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2 years ago

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The difference between the two molar specific heats of a gas is 8000J/kgK. If the ratio of the two specific heats is 1.65, calcu

late the two molar specific heats.

1 answer:

Serjik [45]2 years ago

4 0

Answer:

sorry

Explanation:

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A badminton player shuffles his shoes in resins explain the scientific reason behind this

Kobotan [32]

Answer:

To avoid slipping while playing badminton or to increase friction between the shoes and the badminton court or to enhance the grip.

Explanation:

As the question is general so I will try answer it generally.

As badminton court is usually slippery and flat with no or very little friction and while playing badminton, players have to move very fast from place to place.

So, in order to effectively move faster to take the difficult shots with accuracy badminton players increase the friction between their shoes and the badminton court by shuffling resin to their shoes. It helps to enhance the grip.

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2 years ago

Consider an optical cavity of length 40 cm. Assume the refractive index is 1, and use the formula for Icavity vs wavelength to p

Bad White [126]

Answer:

Diode Lasers

Consider a InGaAsP-InP laser diode which has an optical cavity of length 250

microns. The peak radiation is at 1550 nm and the refractive index of InGaAsP is

4. The optical gain bandwidth (as measured between half intensity points) will

normally depend on the pumping current (diode current) but for this problem

assume that it is 2 nm.

(a) What is the mode integer m of the peak radiation?

(b) What is the separation between the modes of the cavity? Please express your

answer as Δλ.

(c) How many modes are within the gain band of the laser?

(d) What is the reflection coefficient and reflectance at the ends of the optical

cavity (faces of the InGaAsP crystal)?

(e) The beam divergence full angles are 20° in y-direction and 5° in x-direction

respectively. Estimate the x and y dimensions of the laser cavity. (Assume the

beam is a Gaussian beam with the waist located at the output. And the beam

waist size is approximately the x-y dimensions of the cavity.)

Solution:

(a) The wavelength λ of a cavity mode and length L are related by

n

mL

2

λ = , where m is the mode number, and n is the refractive index.

So the mode integer of the peak radiation is

1290

1055.1

10250422

6

6

= ×

××× == −

−

λ

nL

m .

(b) The mode spacing is given by nL

c f 2

=Δ . As

λ

c f = , λ

λ

Δ−=Δ 2

c f .

Therefore, we have nm

nL f

c

20.1

)10250(42

)1055.1(

2 || 6

2 2 26

= ×××

× ==Δ=Δ −

− λλ λ .

(c) Since the optical gain bandwidth is 2nm and the mode spacing is 1.2nm, the

bandwidth could fit in two possible modes.

For mode integer of 1290, nm

m

nL 39.1550

1290

10250422 6

= ××× ==

−

λ

Take m = 1291, nm

m

nL 18.1549

1291

10250422 6

= ××× ==

−

λ

Or take m = 1289, nm

m

nL 59.1551

1289

10250422 6

= ××× ==

−

λ .

Explanation:

8 0

2 years ago

An electron at Earth's surface experiences a gravitational force meg. How far away can a proton be and still produce the same fo

kondaur [170]

I will discuss what is a gravitational force since no figures are attached or given. An objects weight is dependent upon its location in the universe because they exhibit gravitational waves. For example, the earth is a massive planet. Because of its massiveness, it exhibits a strong gravitational force within it. In turn, the objects near the earth will be attracted to it and thereby feels a much stronger gravity on earth. That is why bodies of water, despite its liquid features, stick to the earth. The heavier the body is, the stronger its gravitational pull. Another example is the Milky Way Galaxy, there is a gravitational pull because it is to other galaxies. Also, other galaxies are heavier than the earth and therefore, it is attracted to the Milky Way galaxy because of its gravitational pull.

7 0

2 years ago

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An ideal gas at temperature t0 is slowly compressed at constant pressure of 2 atm from a volume of 10 liters to a volume of 2 li

Sati [7]

<span>Answer: 1600 J

Explanation:

1) Data:

a) ideal gas: ⇒ pV = nRT and work = ∫ pdV
b) slowly compressed ⇒ constant temperature and not heat exchange
c) pressure: p = 2 atm
d) intitial volume: Vi = 10 liters
e) final volumen: Vf = 2 liters.
f) then the volume of the gas is held constant ⇒ not work in this stage.
g) calculate the work done on the gas: W = ?

2) Equation

W = ∫pdV

3) Solution:

Since p = constant, W = p ∫dV = p ΔV = p (Vf - Vi)

p = 2 atm × 1.0 ×10⁵ Pa / atm = 200.000 Pa

Vi = 10 liter × 0.001 m³ ./ liter = 0.01 m³

Vf = 2 liter × 0.001 m³ / liter = 0.002 m³

W = 200.000 Pa × (0.002 m³ - 0.01m³) = - 1.600 J.

The negative sign means the work is done over the system.

That is all the work in the system because at the second stage the volume is held constant.
</span>

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2 years ago

A charge is moving in a magnetic field that points to the left. What direction can the charge move and experience no magnetic fo

tiny-mole [99]

The answer is left and right.

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2 years ago

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