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1 year ago

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The difference between the two molar specific heats of a gas is 8000J/kgK. If the ratio of the two specific heats is 1.65, calcu

late the two molar specific heats.

1 answer:

Serjik [45]1 year ago

4 0

Answer:

sorry

Explanation:

pls search on google

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The Lamborghini Huracan has an initial acceleration of 0.85g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode al

SashulF [63]

Answer:

7.9 $\frac{m}{s^{2} }$

Explanation:

Take the fact that mass is inversely proportional to accelertation:

m ∝ a

Therefore m = a, but because we are finding the change in acceleration, we would set our problem up to look more like this:

$\frac{m_{1} }{m_{2} } = \frac{a_{2} }{a_{1} } \\$

Using algebra, we can rearrange our equation to find the final acceleration, $a_{2}$ :

$a_{2} = \frac{a_{1}*m_{1} }{m_{2} } \\$

Before plugging everything in, since you are being asked to find acceleration, you will want to convert 0.85g to m/s^2. To do this, multiply by g, which is equal to 9.8 m/s^2:

0.85g * 9.8 $\frac{m }{s^{2} }$ = 8.33 $\frac{m }{s^{2} }$

Plug everything in:

7.9 $\frac{m }{s^{2} }$ = $\frac{ 8.33\frac{m}{s^{2} }*1510kg }{1590kg}$

(1590kg the initial weight plus the weight of the added passenger)

8 0

1 year ago

Passengers on a carnival ride move at constant speed in a horizontal circle of radius 5.0 m, making a complete circle in 4.0 s.

Nataliya [291]

Answer:

bonita sisisisiisisisisiisissiissiisiiss

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1 year ago

A 3.0-kg cart moving to the right with a speed of 1.0 m/s has a head-on collision with a 5.0-kg cart that is initially moving to

Maurinko [17]

Answer:

$v = 0.8 m/s$ towards left

Explanation:

As we know that there is no external force on the system of two cart so total momentum of the system is conserved

so we will say

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

now plug in all data into the above equation

$3(1) + 5(-2) = 3(-1) + 5 v$

here we assumed that left direction of motion is negative while right direction is positive

so we can solve it for speed v now

$3 - 10 = - 3 + 5 v$

$5 v = -4$

$v = -0.8 m/s$

3 0

2 years ago

Car B is following Car A and has a greater speed than Car A. the two cars are moving in a straight line and in the same directio

ElenaW [278]

Answer:

Collision force will be same in both the cases.

Explanation:

A perfectly inelastic collision is said to take place when a system loses the amount of its Kinetic Energy at its maximum. In a perfectly inelastic collision, the colliding particles stick to each other. In such a collision, kinetic energy is lost by combining the two bodies with each other.

In situation 1:

Speed of Car A, $v_{A} = 10 mph$

Speed of Car B, $v_{B} = 20 mph$

Relative speed of car A and car B, $v = v_{b} - v_{a} = 10 m/s$

Now, in the situation 2:

Speed of car A, $v_{A} = 30 mph$

Speed of car B, $v_{B} = 40 mph$

Relative speed of car A and car B, $v = v_{b} - v_{a} = 10 m/s$

Therefore, Car A and Car B both have the same relative speed, v = 10 m/s

7 0

1 year ago

A geologist is studying the shore along a river. She finds a pile of rocks at the base of a riverbank. These broken rock pieces

krok68 [10]

erosion caused by the river flow

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1 year ago

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