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DENIUS [597]
2 years ago
11

Write a hypothesis about how the force applied to a cart affects the acceleration of the cart. Use the "if . . . then . . .becau

se . . .” format and be sure to answer the lesson question: "How do force and mass affect the acceleration of an object?”
Physics
2 answers:
Natasha_Volkova [10]2 years ago
8 0

Answer:

"If the force applied to a cart is increased, then the acceleration of the cart increases, because acceleration is directly proportional to the force applied. If the mass of the cart is increased, then the acceleration decreases, because acceleration is inversely proportional to the mass."

Explanation:

This sentence can be explained by Newton's second law:

F=ma

where

F is the net force acting on the cart

m is the mass of the cart

a is the acceleration of the cart

We can re-write it solving for a:

a=\frac{F}{m}

this way, we see that:

- acceleration is directly proportional to the force: if the force increases, the acceleration increases

- acceleration is inversely proportional to the mass: if the mass increases, the acceleration decreases

Lesechka [4]2 years ago
7 0
"If one increases the force on an object, its acceleration increases too because the push it feels is greater"

We have the 2nd law of Newton that relates the 3 concepts; F=m*a. We have that if the mass of an object increases (put weight in luggage), the accelearation decreases; in fact it is inversely proportional to the mass. Hence if the mass is doubled, acceleration is halved. Accelerations is proportional to force; if one doubles the force, the acceleration doubles too.
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Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c
Temka [501]

Answer:

F=ma is the relationship where, F is force, m is mass and a is acceleration.

Newton's second law states that  the unbalanced force applied to the object accelerates the object which is directly proportional to the force and inversely to the mass.

If we apply force to a toy car then It will accelerate.

This is how Newton's second law of motion is verified.

6 0
1 year ago
Read 2 more answers
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end
iragen [17]

Answer:

The workdone is  W_d =-4400J

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

            The force is on the force gauge  F = 2750 N

             The distance that Magnus pulled the bus  d = 1.60m

Generally  the workdone by the tension force on Magnus is

                  Workdone = Force * displacement \ in \ the \ direction \ of \ force

                     W_d = F * (-d)

This negative sign show that is tension force  is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

                   Workdone  =  - 2750 * 1.60

                                     =-4400 J

7 0
2 years ago
A small mass m is tied to a string of length L and is whirled in vertical circular motion. The speed of the mass v is such that
adell [148]

Answer:

(mv^2/R)/(mg)=1/2

v^2=R/2g

7 0
2 years ago
two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb dire
valentinak56 [21]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

The moment of the resultant of these two forces with respect to O 376 lb-ft CCW which is <span>about moment center point O.</span>
6 0
1 year ago
A 5.0-kg crate is resting on a horizontal plank. The coefficient of static friction is 0.50 and the coefficient of kinetic frict
Harlamova29_29 [7]

Answer:

The mass of the crate is 5kg.

We know that the force of friction can be obtained by:

F = N*k

where k is the coefficient of friction, where we use the static one if the object is at rest, and the kinetic one if the object os moving. N is the normal force

If we tilt the base making an angle of 30° with the horizontal, now the normal force against the plank will be equal to the fraction of the weight in the direction normal to the surface of the plank.

Knowing that the angle is 30°, then the fraction of the weight that pushes against the normal is Cos(30°)*W = cos(30°)*5kg*9.8m/s^2 = 42.4N

The fraction of the force in the parallel direction to the plank (the force that would accelerate the crate downwards) is:

F = sin(30°)*5k*9,8m/s = 24.5N

now, the statical friction force is:

Fs = 42.4N*0.5 = 21.2N

The statical force is less than the 24.5N, so the crate will move downwards, then the force that acts on the crate is the kinetic force of friction:

Fk = 42.4N*0.4 = 16.96N

Then, the total force that acts on the crate is:

total force = F - Fk = 24.5N - 16.69N = 7.54N and the direction of this force points downside along the parallel direction of the plank.

3 0
2 years ago
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