Answer:
a) F = 5.14 10⁻⁸ Hz, f = 4.76 10-8 Hz, b) v = 2.29 m / s, f = 42.5 Hz
Explanation:
a)This problem has two parts.
For the calculations relative to the planet Venus, we use that the period and the frequency are related
f = 1 / T
frequency of the orbit around the Sun
Let's reduce the period to the SI system
T = 225 days (24h / 1days) (3600 s / 1h) = 1.94 10⁷ s
F = 1 / 1.94 10⁷
F = 5.14 10⁻⁸ Hz
rotation frequency
T = 243 d = 2.1 107 s
f = 1 / T
f = 1 / 2.1 107
f = 4.76 10-8 Hz
b) give the data of some marine waves
the speed of the wave can be found with kinematics
v = x / t
v = 50.0 / 21.8
v = 2.29 m / s
If the wavelength is L = 9.28m
this distance is the distance between two consecutive ridges or valleys
λ / 2 = L
λ = 2L
λ = 2 9.28
λ = 18.56 m
the speed of the wave is
v = λ f
f = v /λ
f = 2.29 / 18.56
f = 42.5 Hz
Answer:
the net force is 101587.5 N
Explanation:
The speed of wind
v = 30 m/s
The area of roof,
A = 175 m 2
The expression for the Bernoulli's theorem.
P = 12 ρv 2 ...... (1)
Here,
P is the pressure difference,
ρ is the density of air and
v is the speed of wind.
The expression for the pressure.
P = F A ..... (2)
Here,
F is the force and
A is the area of roof.
Part (a)
Substitute the values for the pressure difference in equation (1)
P = 12 × 1.29 × (30) 2 P = 580.5 Pa
Thus, the pressure difference at the roof between the inside and outside air is
580.5 Pa
Part (b)
Substitute the values for the net force in equation (2)
580.5 = F 175 F = 101587.5 N
Thus, the net force is 101587.5 N.
Yes a small child can play with fat child in the seesaw because if the the load distance is decreased the effort will increase. That's means if the distance between the fat boy and the fulcrum is decreased the small child needs less effort.so,he can play
Answer:
Option B and C are True
Note: The attachment below shows the force diagram
Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂;
w = T₁/cos 60° -----(1)
w = T₂/cos 30° ----(2)
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°
T₁ cos 30° = T₂ cos 60°
T₂/T₁ = cos 30°/cos 60°
T₂/T₁ =1.73
Therefore, option a is false since T₂ > T₁
Option B is true since T₁ cos 30° = T₂ cos 60°
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
Answer:
Part a)

Part b)

Part c)

Explanation:
Part a)
The height of the diving board is given as

now the speed of the diver is given as

when the diver will jump into the water then his displacement in vertical direction is same as that of height of diving board
So we will have



Part b)

plug in the values in the above equation


Part c)
Horizontal distance moved by the diver is given as



so the distance from the edge of the pool is given as

