Answer:
Explanation:
The problem must be addressed through the concepts of electromotive force. By Faraday's law it is defined that
Where
Electromotive Force
N = Number of Loops
A = Area
B = Magnetic Field (chaging through the time)
From this equation and our values, we need to find the time, then we re-arrange the equation
Therefore the time required for the magnetic field to decrease to zero from its maximum value is
<h3><u>Answer;</u></h3>
<em>Work = 125 joules </em>
<h3><u>Explanation and solution</u>;</h3>
- Work is the product of force and the distance covered. Therefore, Work = force × distance.
- Work is measured in joules.
- Work is also a change in energy, such that work is done when energy changes, so when kinetic energy, or potential energy changes the there is work being done.
Thus; kinetic energy = work done
Kinetic energy = 1/2mv²
= 1/2 × 10× 5²
= 5 × 25
= 125 joules
Hence, work done is 125 joules.
Answer:
V=20cm/s
Explanation:
The average speed is the distance total divided the time total:
First stage:
T1=5s
But, 
(decelerates to rest)
then: 
on the other hand:
X1=75cm
Second stage:
T2=5s
X2=125cm
Finally:
X=X1+X2=200cm
T=T1+T2=10s
V=X/T=20cm/s
It means you can do 550 Newton Meters of work every second. Power is the rate of doing work, I hope this helps
Answer:
294 Joules
Explanation:
From the question;
- Mass of the drum is 10 kg
- The length of inclined surface, OA is 5 m
- The final height of the drum on the plane AB is 3 m
We are required to determine the potential energy of the drum at A
We know that potential energy is given by the formula;
Potential energy = mgh
where m is the mass, g is the gravitational pull and h is the height
Taking g as 9.8 N/kg
Then;
Potential energy = 10 kg × 9.8 N/kg × 3 m
= 294 Joules
Thus, the potential energy of the drum at A is 294 Joules
