Question

A tennis ball is dropped from 1.20 m above the ground. It rebounds to a height of 1.00 m. (a) with what velocity does it hit the ground?

Answer 1

Answer:

The velocity at which it hits the ground is 4.8497 $\frac{m}{s}$.

Given:

Height of the ball = 1.2 meter

To find:

The velocity does it hit the ground = ?

Formula used:

$v^{2} = u^{2} + 2as$

Where v = final velocity of the ball

u = initial velocity of the ball

a = acceleration due to gravity = 9.8 $\frac{m}{s^{2} }$

s = distance travelled by the ball = 1.2 meter

Solution:

A tennis ball is dropped from 1.20 m above the ground.

According to kinematic equation of motion,

$v^{2} = u^{2} + 2as$

Where v = final velocity of the ball

u = initial velocity of the ball = 0 $\frac{m}{s}$

a = acceleration due to gravity = 9.8 $\frac{m}{s^{2} }$

s = distance travelled by the ball = 1.2 meter

Thus,

$v^{2}$ = 0 + 2 × 9.8 × 1.2

$v^{2}$ = 23.52

v = 4.8497 $\frac{m}{s}$

Hence, the velocity at which it hits the ground is 4.8497 $\frac{m}{s}$.