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Mkey [24]
2 years ago
9

Two electrons, each with mass mmm and charge qqq, are released from positions very far from each other. With respect to a certai

n reference frame, electron A has initial nonzero speed vvv toward electron B in the positive x direction, and electron B has initial speed 3v3v toward electron A in the negative x direction. The electrons move directly toward each other along the x axis (very hard to do with real electrons). As the electrons approach each other, they slow due to their electric repulsion. This repulsion eventually pushes them away from each other.
What is the minimum separation r_min that the electrons reach?

Physics
1 answer:
lana66690 [7]2 years ago
3 0

The answer & explanation for this question is given in the attachment below.

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A merry-go-round with a a radius of R = 1.63 m and moment of inertia I = 196 kg-m2 is spinning with an initial angular speed of
kondor19780726 [428]

Answer:

1) L = 299.88 kg-m²/s

2) L = 613.2 kg-m²/s

3) L = 499.758 kg-m²/s

4) ω₁ = 0.769 rad/s

5) Fc = 70.3686 N

6) v = 1.2535 m/s

7) ω₀ = 1.53 rad/s

Explanation:

Given

R = 1.63 m

I₀ = 196 kg-m²

ω₀ = 1.53 rad/s

m = 73 kg

v = 4.2 m/s

1) What is the magnitude of the initial angular momentum of the merry-go-round?

We use the equation

L = I₀*ω₀ = 196 kg-m²*1.53 rad/s = 299.88 kg-m²/s

2) What is the magnitude of the angular momentum of the person 2 meters before she jumps on the merry-go-round?

We use the equation

L = m*v*Rp = 73 kg*4.2 m/s*2.00 m = 613.2 kg-m²/s

3) What is the magnitude of the angular momentum of the person just before she jumps on to the merry-go-round?

We use the equation

L = m*v*R = 73 kg*4.2 m/s*1.63 m = 499.758 kg-m²/s

4) What is the angular speed of the merry-go-round after the person jumps on?

We can apply The Principle of Conservation of Angular Momentum

L in = L fin

⇒ I₀*ω₀ = I₁*ω₁

where

I₁ = I₀ + m*R²

⇒  I₀*ω₀ = (I₀ + m*R²)*ω₁

Now, we can get ω₁

⇒  ω₁ = I₀*ω₀ / (I₀ + m*R²)

⇒  ω₁ = 196 kg-m²*1.53 rad/s / (196 kg-m² + 73 kg*(1.63 m)²)

⇒  ω₁ = 0.769 rad/s

5) Once the merry-go-round travels at this new angular speed, with what force does the person need to hold on?

We have to get the centripetal force as follows

Fc = m*ω²*R  

⇒  Fc = 73 kg*(0.769 rad/s)²*1.63 m = 70.3686 N

6) Once the person gets half way around, they decide to simply let go of the merry-go-round to exit the ride.

What is the linear velocity of the person right as they leave the merry-go-round?

we can use the equation

v = ω₁*R = 0.769 rad/s*1.63 m = 1.2535 m/s

7) What is the angular speed of the merry-go-round after the person lets go?

ω₀ = 1.53 rad/s

It comes back to its initial angular speed

8 0
1 year ago
What is the momentum of a 533 kg blimp moving east at +75 m/s
mylen [45]

Answer:

39975kgm/s due east

Explanation:

Given parameters:

Mass of the blimp  = 533kg

Velocity  = +75m/s due east

Unknown:

Momentum of the body  = ?

Solution:

The momentum of a body is the amount of motion it posses.

 Momentum is the product of mass and velocity;

 

  Momentum = mass x velocity

  Insert the parameters and solve;

    Momentum  = 533 x 75  = 39975kgm/s

The momentum of the body is 39975kgm/s due east

7 0
1 year ago
Two basketball teams are resting during halftime. While they are resting, a truck driver asks them for help pushing his broken d
viva [34]

Answer:

It is a superordinate goal because both teams could have helped with the task.

Explanation:

If both teams pushed then they could have made it happened

7 0
2 years ago
Which of the following statements correctly describes the models put forth by Ptolemy and Copernicus to explain the universe? A.
FrozenT [24]
The correct option is D. 
The model developed by Ptolemy has a lot of inconsistency and during the middle age additional explanation was offered for the claims made by the model. The model was very complicated because it was based on erroneous assumptions.
Copernicus model was simpler and some of his claims were correct.<span />
8 0
1 year ago
Read 2 more answers
The ultimate source of energy that powers the Sun is__________.
dolphi86 [110]

Answer:C

Explanation:

Mass energy of hydrogen fusing into helium

5 0
1 year ago
Read 2 more answers
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